It takes Andre 4 minutes to swim 5 laps.

In this experiment, 10 plots were randomly sampled and each plot was divided in a half, one half was planted with the common variety of tomato and the other half was planted with the new hybrid variety. At harvest time it was measured the pounds per plant harvested and the variable difference was established. This study variable is defined as the difference between the pounds per plant of the hybrid variety minus the pound per plant of the common variety. Symbolized: Xd: Xnew - Xcommon.

The purpose of this experiment is to test whether there is a difference between the yield of both species. This is a classic example of a paired test, in which you want to put two dependent samples to test. The easiest way to recognize this type of test, if it is not specified in the problem, is that both variables are measured in the same sampling unit. In this case, the sampling unit is "one plot" that was divided and both verities of tomatoes were planted on it.

This test is also called "paired samples T-test" and as a statistic, you have to use the Student t.

The data given is:

sample: 10 plots

sample mean: Xd[bar]: 1.05ppp

sample standard deviation Sd: 1.23ppp

If the hybrid has a higher yield, that would mean that the difference between them would be positive if the difference is positive, its safe to assume that the population mean of the difference will be positive as well. Symbolically: μd>0

With this, you can state the hypothesis as:

H₀:μd≤0

H₁:μd>0

α: 0.05

t=<u> Xd[bar] - μd</u> ~ $t_{n-1}$

Sd/n

t $t_{obs}$ = (1.05 - 0) / (1.23/√10) = 2.69

This is a one-tailed test with critical value $t_{9;0.95} = 1.83$

the p-value for this test is also one tailed.

p( $t_{9}$ ≥2.69) = 1-P( $t_{9}$ <2.69) = 1 - 0.9876 = 0.0124

The decision is to reject the null hypothesis.

I hope it helps!

5 0

3 years ago

Write the decimal 0.36 recurring as a fraction in simplest form.

Grace [21]

Answer:

36/100

Have a great day! I'm trying to spread positivity with the corona virus going around so here you go

Suffering, pain, death, what we've been seeing so recent.

It's hard not to focus on it.

You can say the same thing in so many languages yet they mean the same.

Money can't save you from death, nor the things that take your life

we strive to see some happines in our life, smiles back on people faces.

Giving people hope is all theres left hope for a better future. Sad to say things will only get worst for a period of time but there is hope for the better future that will arrive in its own appointed time!

<em>*eliza*</em>

8 0

3 years ago

Read 2 more answers

A landscaping company charges customers for lawn care based on the area of their yards. Mr. Jones was charged $52 for his yard,

crimeas [40]

Answer:

Landscaping Company will charge $80 for Neighbor yard.

Step-by-step explanation:

Given:

Charges of Mr. Jones = $52

Length of Mr. Jones yard = 65 feet

Width of Mr. Jones yard = 40 feet

Now we will find the area of Mr. Jones yard.

Yard is basically in rectangular form.

Hence we can;

Area of yard is equal to product of length of the yard and width of the yard.

Framing in equation we get;

Area of Mr. Jones Yard = $40\times 65 = 2600\ ft^2$

Now Mr. Jones was charged $52 for a yard having Area 2600 sq. ft.

So we will find the per sq. ft charge applied by the company.

Per sq. ft charge will be equal to Charges of Mr. Jones divided by Area of Mr. Jones Yard.

Framing in equation form we get;

Per sq. ft charge = $\frac{52}{2600} = \$0.02$

Hence the Landscaping company charge Mr. Jones at $0.02 per sq.ft.

Now Given:

Length of Neighbor yard = 80 ft.

Width of Neighbor yard = 50 ft.

We need to find the Charges on Neighbor based on charges applied on Mr. Jones.

First we will find the Area of Neighbors yard we get;

Area of Neighbors yard = $80 \times50 = 4000\ ft^2$

Charges of Neighbor yard will be equal to charges Landscaping company for per sq. ft multiplied by area of Neighbors yard.

Framing in equation form we get;

Charges of Neighbor yard = $0.02\times 4000 = \$80$

Hence Landscaping Company will charge $80 for Neighbor yard.

8 0

3 years ago