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dezoksy [38]
3 years ago
7

Whats the mean of the data set 86,90,93,85,79,92​

Mathematics
1 answer:
k0ka [10]3 years ago
4 0

Answer:

87.5

you need to add all the numbers and the divide it by the sum of values

You might be interested in
One number is 4 more than another. the difference between their squares is 64. what are the numbers
lora16 [44]
We have to set up 2 different equations if we are to solve for 2 unknowns.  The first equation is x = y + 4.  One number (x) is (=) 4 more than another (y + 4).  Since we have determined that x is larger (cuz it's 4 more than y), when we set up their difference, we are going to subtract y from x cuz x is bigger.  The second equation then is x^{2} - y^{2} =64.  In our first equation we said that x = y + 4, so let's sub that value in for x in the second equation: (y+4) ^{2} - y^{2} =64.  Expand that binomial to get y^{2} +8y+16- y^{2} =64.  Of course the y squared terms cancel each other out leaving us with 8y + 16 = 64.  Solving for y we get that y = 6.  Subbing 6 in for y in our first equation, x = 6 + 4 tells us that x = 10. Yay!

5 0
3 years ago
3. Product of two numbers is 27/14. If one of them is 1 2/7, find the<br>other.<br>​
Tems11 [23]

Answer:

\frac{9}{8}

Step by step explanation:

\frac{27}{14}  \div  \frac{12}{7}  \\  \:  \:  \:   \:  \:  \:  \:  \:   \:  \:  \:  \: \:  =  \frac{27}{14}   \times  \frac{7}{12}  =  \frac{9}{8}

5 0
3 years ago
I need help on this please anyone help
joja [24]

x + 90 = 7x

90 = 7x - x

90 = 6x

x = 90/6

x = 15

Result x = 15

Measure of each angle = 15 + 90

= 105

a) x = 15

b) angle = 105°

Second problem

a= Complementary

b) 90°

c) x = 90 - 37

x = 53°

8 0
1 year ago
4∣3c+5∣=16c I know the answer is five but I don't know how to get there
Anettt [7]

Answer:

c = 5, explanation for how to get there

Step-by-step explanation:

If we have the equation 4|3c+5| = 16c, we want to isolate c on one side and find it's value.

Let's first divide both sides by 4.

4|3c+5|\div4 = 16c\div4\\\\|3c + 5| = 4c

Now let's solve for the absolute value. We know that:

3c + 5 = 4c

or

3c + 5 = -4c

Possibility 1:

3c + 5 = 4c

Subtract 3c from both sides:

5 = c

Possibility 2:

3c + 5 = -4c

Add 4c to both sides:

7c + 5 = 0

Subtract 5 from both sides:

7c = -5

Divide both sides by 7:

c = \frac{-5}{7}

Plugging both of these values into the equation, we can see that only 5 works.

Hope this helped!

8 0
3 years ago
In ΔABC, what is the value of cos B?
Karo-lina-s [1.5K]
b^{2} = a^{2} + c^{2} -2acCosB
Making cos B the subject;
2acCosB=a^{2} + c^{2} - b^{2}
cosB=\frac{ a^{2} + c^{2} - b^{2} }{2ac}
8 0
3 years ago
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