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Diano4ka-milaya [45]
2 years ago
9

Please help me out!!!!

Mathematics
1 answer:
LuckyWell [14K]2 years ago
7 0

Answer:

the value for x is

11 \sqrt{3}

and the value for y is 11 on the triangle problem we use sin60 to find x and we use tan60 to find y

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(05.01)Which equation can be used to calculate the area of the shaded triangle in the figure below?
Marina86 [1]

Equation of shaded triangle is \frac{1}{2} (14\times8).

Solution:

Length of the rectangle = 14 ft

Breadth of the rectangle = 8 ft

Area of the rectangle = length × breadth

                                    = 14 × 8

In this rectangle the diagonal splits the rectangle into two equal halves.

Area of the shaded triangle = Half of area of rectangle

                                              $=\frac{1}{2} (14\times8)

Area of the shaded triangle = \frac{1}{2} (14\times8)

Hence the equation can be used to calculate the area of the shaded

triangle is \frac{1}{2} (14\times8).

7 0
3 years ago
Please help me with geometry ASAP!!!
Makovka662 [10]

Answer:

asking all these questions why you asking all these questions

Step-by-step explanation:

4 0
2 years ago
Which equation is rewritten in vertex form?
Zinaida [17]
(x + 3)^2 + (x + 4)^2 
= x^2 + 6x + 9 + x^2 + 8x + 16
= 2x^2 + 14x + 25
= 2(x^2 + 7x) + 25
= 2[(x + 7/2)^2  - 49/4] + 25
= 2(x + 7/2)^2 - 98/4 + 25
= 2(x + 7/2)^2 + 1/2


Its B

7 0
3 years ago
Can 3.65909090909 be expressed as a fraction whose denominator is a power of 10? Explain.
GuDViN [60]
\bf 3.659\textit{ can also be written as }\cfrac{3659}{1000}\textit{ therefore }3.6590909\overline{09}\\\\
\textit{can be written as }\cfrac{3659.0909\overline{09}}{1000}

notice above, all we did, was isolate the "recurring part" to the right of the decimal point, so the repeating 09, ended up on the right of it.

now, let's say, "x" is a variable whose value is the recurring part, therefore then

\bf \cfrac{3659.0909\overline{09}}{1000}\qquad \boxed{x=0.0909\overline{09}} \qquad \cfrac{3659+0.0909\overline{09}}{1000}\implies \cfrac{3659+x}{1000}

now, the idea behind the recurring part is that, we then, once we have it all to the right of the dot, we multiply it by some power of 10, so that it moves it "once" to the left of it, well, the recurring part is 09, is two digits, so let's multiply it by 100 then, 

\bf \begin{array}{llllllll}
100x&=&09.0909\overline{09}\\
&&9+0.0909\overline{09}\\
&&9+x
\end{array}\quad \implies 100x=9+x\implies 99x=9
\\\\\\
x=\cfrac{9}{99}\implies \boxed{x=\cfrac{1}{11}}\\\\
-------------------------------\\\\
\cfrac{3659.0909\overline{09}}{1000}\qquad \boxed{x=0.0909\overline{09}} \quad \cfrac{3659+0.0909\overline{09}}{1000}\implies \cfrac{3659+x}{1000}
\\\\\\
\cfrac{3659+\frac{1}{11}}{1000}

and you can check that in your calculator.
8 0
3 years ago
Nayelly is weighing how much of a solid resulted from a chemical reaction on a scale that reads to the nearest 18 ounce. The mea
77julia77 [94]
I think your answer is 680.8
6 0
3 years ago
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