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stiks02 [169]
3 years ago
14

Which relation has both domain and range of all real numbers

Mathematics
1 answer:
Mama L [17]3 years ago
4 0

Answer:

C

Step-by-step explanation:

All real numbers means all numbers positive and negative

Therefore, it would have to be C because the others dont have both positives and negatives for their domain and range reaches

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A circle with radius of \greenD{5\,\text{cm}}5cmstart color #1fab54, 5, start text, c, m, end text, end color #1fab54 sits insid
Marat540 [252]

Answer:

The area of the shaded region is 42.50 cm².

Step-by-step explanation:

Consider the figure below.

The radius of the circle is, <em>r</em> = 5 cm.

The sides of the rectangle are:

<em>l</em> = 11 cm

<em>b</em> = 11 cm.

Compute the area of the shaded region as follows:

Area of the shaded region = Area of rectangle - Area of circle

                                            =[l\times b]-[\pi r^{2}]\\\\=[11\times 11]-[3.14\times 5\times 5]\\\\=121-78.50\\\\=42.50

Thus, the area of the shaded region is 42.50 cm².

7 0
3 years ago
Read 2 more answers
Brainliest if correct.
Bingel [31]
Your answer is 94/15

if mixed, it’s 6 4/15
5 0
3 years ago
Sin(20)=x/670 ????????
mash [69]

Answer:

229.2

Step-by-step explanation:

Remark

There's a lot in this question. The x is not just any x. It is defined and limited by its relationship with the sine function.

The Sin is defined as Opposite over Hypotenuse in a right triangle. The 670 is the Hypotenuse. You know that by the definition of Sine.

So one thing you should always keep in mind: the x because of where it is in the definition, will always be smaller than the Hypotenuse. So you should get a value less than 670.

Formula

Just as you have it

Sin(20) = x / 670

Solution

Multiply both sides by 570

670 * sin(20) = x

sin(20) = 0.3420

x = 670 * 0.3420

x = 229.2

6 0
3 years ago
15x^2 + 41x + 28 <br><br>STEP BY STEP ANSWER PLSSS​
maria [59]

Answer:

(3x+4)(5x+7)

Step-by-step explanation:

15x^2 +41x+28

Factor the expression by grouping. First, the expression needs to be rewritten as 15x^2 +ax+bx+28. To find a and b, set up a system to be solved.

a+b=41

ab=15×28=420

Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 420.

1,420

2,210

3,140

4,105

5,84

6,70

7,60

10,42

12,35

14,30

15,28

20,21

Calculate the sum for each pair.

1+420=421

2+210=212

3+140=143

4+105=109

5+84=89

6+70=76

7+60=67

10+42=52

12+35=47

14+30=44

15+28=43

20+21=41

The solution is the pair that gives sum 41.

a=20

b=21

Rewrite 15x^2 +41x+28 as (15x^2 +20x)+(21x+28).

(15x^2 +20x)+(21x+28)

Factor out 5x in the first and 7 in the second group.

5x(3x+4)+7(3x+4)

Factor out common term 3x+4 by using distributive property.

(3x+4)(5x+7)

7 0
3 years ago
Read 2 more answers
Anybody know this answe cause I don’t
wariber [46]

Answer:

1.875 Pounds

Step-by-step explanation:

8 0
3 years ago
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