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Mashcka [7]
3 years ago
8

which ordered pairs are a solution to the equation? y=2×-3 select all that apply (4,2) (1,-1) (-1,-7) (2,1)​

Mathematics
1 answer:
kirill [66]3 years ago
3 0

To check if a point, such as (1, -1), is on your line, you can either sub in both the x and y values of each point into your line's equation, or one and check if the other matches up with your point.

For example, the x value of (1, -1) is 1, and the y value is -1. Sub these points into your equation:

y = 2x - 3 Original equation

(-1) = 2(1) - 3 Sub in points

-1 = 2 - 3

-1 = -1 Sides equal, therefore point is on line

If a point is NOT on the line:

y = 2x - 3 Original equation

(2) = 2(4) - 3 Sub in points

2 = 8 - 3

2 = 5 Sides do NOT equal, point is NOT on line, NOT a solution

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Answer:

d=2\sqrt{17}\approx8.2462

Step-by-step explanation:

To find the distance between two points, use the distance formula.

The distance formula is:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2

Let (3,-4) be x₁ and y₁ and let (5,4) be x₂ and y₂. Therefore:

d=\sqrt{(5-3)^2+(4--4)^2

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d=\sqrt{(2)^2+(8)^2

Square:

d=\sqrt{4+64}

Add:

d=\sqrt{68}

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6 0
3 years ago
Help please?!
Furkat [3]
Well from what i know here's what i would put........
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