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Bumek [7]
3 years ago
9

PLZ HELP ITS DUE T MIDNIGHT

Mathematics
1 answer:
kkurt [141]3 years ago
5 0
I don’t know the answer but I can tell you how to do it subtract starting value minus final value divide that amount by the absolute value of the starting value multiply by 100 to get percent decrease if the percentage is negative it means there was an increase not a decrease
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Having trouble with this one can someone teach me how to find the slope in this question. Try to help me learn it aswell. Its in
ASHA 777 [7]
Hi there! The answer is -2.

We can find the slope of a formula by using the following formula:

slope = \frac{change \: of \: y}{change \: of \: x} =\frac{y2 - y1}{x2 - x1}
x2 and y2 don't mean squared, but the x and y coordinate of our second point.

First we need to find two points on the line. Ijn this particular case we have (-3, 3) and (1, -5). Now we can fill in the formula.

slope = \frac{ - 5 - 3}{1 - - 3} = \frac{ - 8}{4} = - 2

Therefore, the third answer is correct.
~ Hope this helps you!
7 0
4 years ago
Hunter took a test With 28 questions. If he answered of 2/7 of the questions correctly, how many did he
Vinvika [58]

Answer:20

Step-by-step explanation: If you have a calculator its easy

3 0
3 years ago
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Consider the circle above. What is the approximate area of the circle?
Olin [163]

Answer:

The area of a circle is : π (Pi) times the Radius squared : A = π r 2 or, when you know the Diameter: A = (π /4) × D 2 or, when you know the Circumference: A = C 2 / 4 π

4 0
3 years ago
Help pls if its linear or nonlinear
pshichka [43]

Answer:

linear

Step-by-step explanation:

4 0
3 years ago
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At noon, ship a is 40 nautical miles due west of ship b. ship a is sailing west at 18 knots and ship b is sailing north at 17 kn
igor_vitrenko [27]

The distance between the ships changing at 92.29 Knots

  • Using the position of ship A as the reference point, at time t measured in hours past noon, ship A is 18 t miles west of this point and ship B is 40 + 17t north of this point.
  • The distance between ships is then

                              d(t) = \sqrt{(18t)^{2} + (40+17t)^{2} } \\

The rate of change of distance is -

                              \frac{dd}{dt} = \frac{36t + 2(40 + 17t)17}{2\sqrt{18t^{2} + (40 + 17t) } }

after putting t = 5 into this rate of change ,

we get, answer = 92.29

To learn more about differentiation from the given link

brainly.com/question/25081524

#SPJ4

4 0
2 years ago
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