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Bumek [7]
2 years ago
9

PLZ HELP ITS DUE T MIDNIGHT

Mathematics
1 answer:
kkurt [141]2 years ago
5 0
I don’t know the answer but I can tell you how to do it subtract starting value minus final value divide that amount by the absolute value of the starting value multiply by 100 to get percent decrease if the percentage is negative it means there was an increase not a decrease
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Beef hope me I need you to answer the question. What is n * 54 - 688-20 =???³
blsea [12.9K]

Answer:n= 1/3d - 2/3m

Step-by-step explanation:

d=2m+3n

Step 1: Flip the equation.

2m+3n=d

Step 2: Add -2m to both sides.

2m+3n+−2m=d+−2m

3n=d−2m

Step 3: Divide both sides by 3.

3n/3 = d-2m/3

Therefore

n= 1/3d - 2/3m

Hope this helps!

Plz name brainliest if possible.

1jaiz4 and 1 more users found this answer helpful

THANKS

1

5.0

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Answer

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maxtext75

Helping Hand

15 answers

26 people helped

Answer:

n = d - 2m

        3*

Step-by-step explanation:

First we want to get n alone on one side, so we should subtract 2m from both side;

d = 2m + 3n

3n = d - 2m

Now to get n by itself, we need to divide by 3 from both sides;

3n = d - 2m

n = d - 2m

        3*

*Pretend there is a fraction bar between d - 2m and 3

Step-by-step explanation:

7 0
3 years ago
Please answer quickly!
salantis [7]

Answer:

0/6 <--------------------------

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Which graph represents a function?
Vilka [71]

Answer:

Bottom right

Step-by-step explanation:

For a graph to represent a function, each input must only have one output.

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2 years ago
Show that each statement is true: <br> Cos^4X-sin^4X=2cos^2X-1
Ivan
cox^4x-sin^4x=2cos^2x-1\\\\&#10;(cosx^2-sin^2x)(cosx^2x+sin^2x)=2cos^2x-1\\\\&#10;cosx^2-sin^2x*1=2cos^2x-1\ \ \ | subtract\ 2cos^2x\\\\&#10;-cosx^2-sin^2x=-1\ \ \ | multiply\ by\ -1\\\\&#10;cosx^2+sin^2x=1\\\\&#10;1=1
4 0
3 years ago
I just need answers to the odd numbered questions.<br> I would appreciate the help<br><br> 35 points
Misha Larkins [42]

Answer:

Step-by-step explanation:

Combine real terms and combine complex terms

1) 3 + 2i + 2 - 5i = 3 +2 + 2i - 5i

                          = 5 + (2-5)i

                          = 5 + (-3)i

                          = 5 - 3i

3) 2 - (1 - 2i) + (4 -5i ) - (1 - 3i)  = 2 -1 + 2i + 4 - 5i - 1 + 3i

           {- is distributed to (1 - 2i) & - is distributed to (1- 3i)}

              = 2 - 1  + 4 + 1 + 2i - 5i + 3i

              = 6 +0i = 6

5) 4 - 3i + 4 + 3i = 4 +4 -3i + 3i

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7) (3 - 2i)² + (3 +2i) = 3² - 2*3*2i + (2i)² + 3 + 2i     {(a - b)² = a² - 2ab +b²}

= 9 -12i + 4i² + 3 + 2i

= 9 - 12i + 4*(-1) + 3 + 2i       {i²  = -1}

= 9 +3 - 4 - 12i +2i

= 8 - 10i

9) (a +b)^{4} - (a - b)^{4} = 8ab(a^{2} +b^{2})\\\\\\Here, \ a = 1 \ and \ b = i\\\\\\(1+\sqrt{-1})^{4}-(1-\sqrt{-1})^{4}=(1+\sqrt{i^{2}})^{4}-(1-\sqrt{i^{2}})^{4}\\\\=(1+i)^{4}-(1-i)^{4}\\\\=8*1*i(1^{2}+i^{2})\\\\=8i*(1 -1)\\\\=8i*0\\\\=0

6 0
3 years ago
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