Question

Which equation represents the line that passes through points (1, –5) and (3, –17)?

Answer 1

Answer:

y = -6x + 1

Step-by-step explanation:

y = mx + b

b = slope = (-5 - (-17))/(1 - 3) = 12/(-2) = -6

y = -6x + b

-5 = -6(1) + b

b = 1

y = -6x + 1

Answer 2

Answer:

$y=-6x+1$

Step-by-step explanation:

The linear equation with slope m and intercept c is given as follows:

$y=mx+c$

The formula for slope of line with points $(x_{1} ,y_{2} )$ and $(x_{2} ,y_{2} )$ can be expressed as,

$m=\frac{y_{2} -y_{1} }{x_{2} -x_{1} }$

The line passes the points that are $(1,-5)$ and $(3,-17)$

The slope of the line can be obtained as follows:

$m=\frac{-17-(-5)}{(3)-1}$

$m=\frac{-12}{2}$

$m=-6$

The slope of the line is $-6$

The line passes through the point $(3,-17)$

Substitute 3 for x, - 6 for m and -17 for y in equation $y=mx+c$ to obtain the value of c.

$-17=-6(3)+c$

$-17=-18+c$

$-17+18=c$

$1=c$

The equation is $y=-6x+1$

Hence, the equation of the line that passes through the points $(1,-5)$ and $(3,-17)$ is $y=-6x+1$