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Grace [21]
3 years ago
6

What are three integers that do not all have the same sign that have a sum of -20. Write three integers that do not all have the

same sign that have a sum of 10
Mathematics
1 answer:
Ratling [72]3 years ago
8 0

There isn't an unique solution to these equations. For example, for the first one, you may pick two arbitrary positive number, and fix the third so that the sum is -20.

Say that you choose 4 and 26. Their sum is 30. To reach -20, the third number must be -50.

So, 4, 26 and -50 are three numbers that sum to -20 and don't have all the same sign.

Similarly, for the second requirement, pick two negative numbers, and adjust the third.

If you choose -3 and -2, their sum is -5. So, the third must be 15. In fact, -3, -2 and 15 are three numbers that sum to 10 and don't have all the same sign.

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2 years ago
Pick the numerical expression for: 2 minus b<br> A.2 - b<br> B.b-2<br> C. 2 X b<br> D.b : 2
Ivanshal [37]
I think the answer would be A
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3 years ago
A garden table and a bench cost 816 combined. The garden table costs 84 less than the bench. What is the cost of the bench?
klemol [59]

Answer:

366

Step-by-step explanation:

A garden table and bench cost 816 when combined together

The garden table cost 84 less than the bench

Therefore the price of the bench can be calculated as follows

x + (x+84)= 816

2x+84= 816

2x= 816-84

2x= 732

Divide both sides by 2

x= 732/2

= 366

Hence the price of the bench is 366

5 0
3 years ago
A box is being created out of a 15 inch by 10 inch sheet of metal. Equal-sized squares are cutout of the corners, then the sides
ivolga24 [154]

Answer:

Therefore the dimensions of the square should be 0.1528 inch by 0.1528 inch so, the box  has largest volume.

Step-by-step explanation:

Given that,

A box is being created out of a 15 inches by 10 inches sheet of metal.

The length of the one side of the squares which are cut out of the each corners of the metal sheet be x.

The length of the metal box be = (15-2x) inches.

The width of the metal box be =(10-2x) inches

The height of the metal box be =x inches

Then, the volume of the metal box= length×width×height

                                                         =(15-2x)(10-2x)x cubic inches

                                                         =(150x-50x²+4x³) cubic inches

∴ V= 4x³-50x²+15x

Differentiating with respect to x

V'=12x²-100x+15

Again differentiating with respect to x

V''=24x-100

For maximum or minimum value, V'=0

12x²-100x+15=0

Apply quadratic formula x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}, here a=12, b= -100 and c=15

x=\frac{-(-100)\pm\sqrt{(-100)^2-4.12.15}}{2.12}

\Rightarrow x=\frac{100\pm\sqrt{9280}}{2.12}

\Rightarrow x=0.1528,8.18

For x= 8.18, The value of (15-2x) and (10-2x) will negative.

∴x=0.1528 .

Now, V''|_{x=0.1528}=24(0.1528)-100

∴At x=0.1528 inch, the volume of the metal box will be maximum.

Therefore the dimensions of the square should be 0.1528 inch by 0.1528 inch so, the box  has largest volume.

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