If He began at 4:15 and ended at 5:50 then that would be 95 minutes
The answer is the second one
Hope this helps!
Answer:
.
See the diagram attached below.
Let the chords be AB and AC with common point A.
AD is the diameter. Join B with D and C with D to form two triangles.
We need to prove that AB=AC.
\begin{gathered}In\ \triangle ABD\ and \triangle ACD;\\Given\ that\ \angle BAD=\angle CAD----(condition\ 1)\\since\ AD\ is\ diameter, \angle ABD=\angle ACD = 90^0\\So\ \angle ADB=\angle ADC--------(condition\ 2)\\AD=AD\ (common\ side)-----(condition\ 3)\\ \\So\ the\ triangles\ are\ congruent\ by\ ASA\ rule.\\Hence\ AB=AC.\end{gathered}
In △ABD and△ACD;
Given that ∠BAD=∠CAD−−−−(condition 1)
since AD is diameter,∠ABD=∠ACD=90
0
So ∠ADB=∠ADC−−−−−−−−(condition 2)
AD=AD (common side)−−−−−(condition 3)
So the triangles are congruent by ASA rule.
Hence AB=AC.
5) Transitive property of equality
6) Addition property of equality
7) Subtraction property of equality
8) Division property of equality
9) Multiplication property of equality
10) Transitive property of congruence
11) Substitution property of equality
12) Addition property of equality [add XY to both sides then use segment addition postulate]
13) Subtraction property of equality [subtract XY from both sides then use segment subtraction postulate]
14) Angle addition postulate
15) Addition property of equality [add angle 2 to both sides then use angle addition postulate]
16) Transitive property of equality
Answer: ]1, 2[
Step-by-step explanation:
![A \cap B=[0; 2[\\\\(A \cap B)-C=]1, 2[](https://tex.z-dn.net/?f=A%20%5Ccap%20B%3D%5B0%3B%202%5B%5C%5C%5C%5C%28A%20%5Ccap%20B%29-C%3D%5D1%2C%202%5B)
