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oksian1 [2.3K]
3 years ago
15

Select the statement that describes the expression 5 x (8 − 5) ÷ 3.

Mathematics
1 answer:
lys-0071 [83]3 years ago
8 0

Step-by-step explanation:

Substitution: ‘Find the value of 2x + 3 if x = 4.’ In this case the pronumeral is given the value 4.

Solving an equation: ‘Find x if 2x + 3 = 8.’ Here we are seeking the value of the pronumeral that makes the sentence true.

Identity: ‘The statement of the commutative law: a + b = b + a.’ Here a and b can be any real numbers.

Formula: ‘The area of a rectangle is A = lw.‘ Here the values of the pronumerals are connected by the formula.

Equation of a line or curve: ‘The general equation of the straight line is y = mx + c.’

Here m and c are parameters. That is, for a particular straight line, m and c are fixed.

In some languages other than English, one distinguishes between ‘variables’ in functions and ‘unknown quantities’ in equations (‘incógnita’ in Portuguese/Spanish, ‘inconnue’ in French) but this does not completely clarify the situation. The terms such as variable and parameter cannot be precisely defined at this stage and are best left to be introduced later in the development of algebra.

An algebraic expression is an expression involving numbers, parentheses, operation signs and pronumerals that becomes a number when numbers are substituted for the pronumerals. For example 2x + 5 is an expression but +) × is not.

Examples of algebraic expressions are:

3x + 1 and 5(x2 + 3x)

As discussed later in this module the multiplication sign is omitted between letters and between a number and a letter. Thus substituting x = 2 gives

3x + 1 = 3 × 2 + 1 = 7 and 5(x2 + 3x) = 5(22 + 3 × 2) = 30.

In this module, the emphasis is on expressions, and on the connection to the arithmetic that students have already met with whole numbers and fractions. The values of the pronumerals will therefore be restricted to the whole numbers and non-negative fractions.

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Nutka1998 [239]

Answer:

To construct a dilation, we need the center of dilation, which is the point from which we make the image smaller or larger. We also need a scale factor, which is the number that determines how large or small we are making the new image. If the scale factor is greater than 1, we have an enlargement, because the new image will be larger than the original image. If the scale factor is less than 1, we have a reduction because the new image will be smaller than the original image.

Enlargement

Step-1

Let's dilate triangle PQR by a scale factor of 2 with a center of dilation at point C.

Step-2

First, we will use a straightedge to connect the center of dilation C to each vertex. We are going to extend those lines across the whole page.

Step-3

Next, we'll place the point of the compass on the center of dilation C and the pencil on vertex Q and measure that distance.

Step-4

Now, without changing the size of the compass, we will move the point of the compass to vertex Q, and make a mark on the line that is extended through Q.

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Notice that since we measured the distance from C to Q and then used that same distance to mark the line, we have now created a new point that is twice the distance from C that Q was.

We now repeat the process for each of the other vertices of the triangle.

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These marks represent the vertices of our dilated image. We often use the same letters with an apostrophe to show that it is the corresponding vertex.

Step-7

Finally, we use the straightedge to connect all of the new vertices.

Now,See how triangle P

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Q

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is twice the size of the original triangle.

Reduction

Step-1

Given triangle PQR, now let's dilate the image with a center of dilation at C and with a scale factor of

2

1

Step-2

Using the straightedge, we will connect all of the vertices to the center of dilation C. In this case, since our scale factor is less than 1, we are reducing the size of the triangle.

Step-3

The green lines are the new lines that we have drawn.

Since we have to reduce the size of the triangle by half, we want to cut the distance in half from each vertex to the center of dilation. In order to do this, we will set our compass to a distance that is more than halfway between vertex P and point C but less than the total distance.

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Keeping the compass at that same distance, start with the point of the compass on vertex P, then draw a curve that intersects the line between P and C. Next, keeping the compass at the same distance, place the point of the compass on C and draw a curve that intersects the line between P and C and intersects the previously drawn curve.

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Now, we will take the straightedge and connect the points where the curves overlap.

4 0
3 years ago
What is the quotient of 83.3 and 24.5
Svetradugi [14.3K]

Answer:

3.4

Step-by-step explanation:

83.3 divided by 24.5= 3.4

5 0
3 years ago
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mrs_skeptik [129]
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5 0
3 years ago
Find the circumference of the circle.
SashulF [63]

Answer:

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Step-by-step explanation:

Given

The radius of the circle = r = 5 in

We know that diameter is twice the radius.

so d = 2r = 2(5) = 10 in

<u>Finding the circumference of the circle in terms of pi</u>

Using the formula to find the circumference of the circle

C = dπ

C = 10×π

C = 10π inches

Thus, the circumference of the circle in term of pi = 10π inches

<u>Finding the circumference of the circle using π = 3.14</u>

We know that the formula to find the circumference of the circle

C = dπ

Given

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substituting π = 3.14 to find the circumference of the circle

C = 10×3.14

C = 31.4 inches

Thus, the circumference of the circle = 31.4 inches

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Tema [17]

Answer:true

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3 years ago
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