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Rashid [163]
3 years ago
14

What is the circumference

Mathematics
1 answer:
jeka943 years ago
7 0

Answer:

<em><u>C=139.80</u></em>

Step-by-step explanation:

C=2πr

=2π(22.25)

=139.80

<em>C=</em><em>1</em><em>3</em><em>9</em><em>.</em><em>8</em><em>0</em>

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Pavlova-9 [17]
Since there should be 180 in a tringle the bottom triangle woul be 65 65 50. assuming that the lines / and \ are the same in both traingles that means that at intersection they create the same angles above=below and left=right meaning the answer to x is x=50 
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For the graph, what is a reasonable constraint so that the function is at least 300?
blsea [12.9K]

Answer:

C) 0 ≤ x ≤ 25

Step-by-step explanation:

We are supposed to find a reasonable constraint so that the function is at least 300 i.e. the value of x at which f(x) is greater or equal to 300

A)x ≥ 0

Refer the graph

At x = 0

f(x)=300

On increasing the value of x , f(x) increases but at x = 12 it starts decreasing

So, x ≥ 0 can also have f(x)<300

So, Option A is wrong

B)−5 ≤ x ≤ 30

At x = -5

f(x) = 100

So, Option B is wrong since we require f(x) is greater or equal to 300

c)0 ≤ x ≤ 25

At x = 0

f(x)=300

At x = 12 , it starts decreasing

At x = 25

f(x)=300

So, The value of f(x) is at least 300 when 0 ≤ x ≤ 25

D)All real numbers

At x = 30

f(x)=0

But we require f(x) greater or equal to 300

Hence Option C is true

8 0
3 years ago
The function f(x) = −(x + 5)(x + 1) is shown. What is the range of the function? all real numbers less than or equal to 4 all re
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all real numbers such that y is less than or equal to 4

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3 years ago
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Can you please show working out for $4,000 at 3% for 4 years
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5 0
3 years ago
12, 9, 15, 19, 20, 15<br><br> Mean <br><br> Median <br><br> Mode
Ede4ka [16]

Answer:

Mean: 15

Median:  15

Mode:  15

Step-by-step explanation:

<h2>Definitions:</h2>

<u>Mean</u>: It represents the average value of a given data set. The formula for finding the mean of a given set of numbers by taking the quotient of all numbers and the number of values. In other words:

\displaystyle\mathsf{Mean\:=\:\frac{Sum\:of \:all\: values}{Number\:of\:values \:in\: a \:given \:data\:set}}

<u>Median:</u> It represents the middle value in a given set of numbers. In order to determine the median, it is essential to arrange the given data either in <em>ascending</em> or <em>descending</em> order (although it is customary to arrange the numbers into ascending order).

  • If there is an odd number of values in a given set, then the <u>middle number</u> is the median of that set.
  • If a given list comprises of an even number of items, then we must take the <em>average</em> of the two middle numbers.

<u>Mode</u>: It represents the number that <u>occurs most often</u> on a list of items or data.

<h2>Solution:</h2><h3><u>Find the Mean:</u></h3>

Using the formula provided in the previous section for finding the mean:

\displaystyle\mathsf{Mean\:=\:\frac{Sum\:of \:all\: values}{Number\:of\:values \:in\: a \:given \:data\:set}}

\displaystyle\mathsf{Mean\:=\:\frac{12+9+15+19+20+15}{6}\:=\:\frac{90}{6}\:=\:15}

<h3><u>Find the Median:</u></h3>

Arrange the given data set in <u><em>ascending order</em></u>:

12, 9, 15, 19, 20, 15  ⇒  9, 12, <u>15</u>, <u>15</u>, 19, 20

Next, since there is an even number of items on our given data set, we must <u>take the average of the</u><u> two middle numbers</u> (which are 15 and 15):

\displaystyle\mathsf{Median\:=\:\frac{15+15}{2}\:=\:\frac{30}{2}\:=\:15}

Therefore, the median is 15.

<h3><u /></h3><h3><u>Find the Mode:</u></h3>

As described in the previous section of this post, the mode is the number that occurs most often on our given data. The only repeating number on our list is 15, hence it is the mode.

Therefore, the <em>mean</em>, <em>median</em>, and <em>mode</em> of the given data set is <u>15</u>.

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2 years ago
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