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Rashid [163]
3 years ago
14

What is the circumference

Mathematics
1 answer:
jeka943 years ago
7 0

Answer:

<em><u>C=139.80</u></em>

Step-by-step explanation:

C=2πr

=2π(22.25)

=139.80

<em>C=</em><em>1</em><em>3</em><em>9</em><em>.</em><em>8</em><em>0</em>

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Answer:

10

Step-by-step explanation:

we can solve this using basic algebra

We set up the equation using the info that each video costs $5 and that we but 12 of them

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(Please note: 1x = x)

12(5) + x = 70

60 + x = 70

60 - 60 + x = 70 - 60

x = 10

3 0
3 years ago
The points (k, -8) and (8,0) fall on a line with a slope of 8. What is the value of k?<br> k=
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2 years ago
I need help! I have test tomorrow and I got sick so I couldn’t go to school and I’m lost
Elan Coil [88]
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3 years ago
In the problem below, AB, CD, and EF are two-digit numbers, where A, B, C, D, E and F represent distinct digits from 1 to 9. Is
Oksi-84 [34.3K]

Answer:

<em>When both the conditions hold true, F is prime.</em>

Step-by-step explanation:

AB, CD, and EF are two-digit numbers, where A, B, C, D, E and F represent distinct digits from 1 to 9.

  AB

+ CD

--------

  EF

1st condition, B and D are consecutive.

Adding B and D gives us F.

Possible values can be (F being the unit value after adding not considering the carry over):

B + D = F

1+2=3

2+3=5

3+4=7

4+5=9

5+6=1

6+7=3

7+8=5

8+9=7

Here F is not prime (because 9 is not prime).

Now, let us consider the 2nd condition as well.

i.e. C = 8

For the following

  AB

+ CD

--------

  EF

C is 8 then A must be 1 because any value other than 1 for A will make the sum of A and C greater than 9 and there will be a carry which is not the case here.

So, E = 8 + 1 = 9

Now, B  and D are consecutive and can not be 1, 8 or 9.

So, possible values are:

B + D = F

2 + 3 = 5

3 + 4 = 7

Here F is prime.

So, when both the conditions hold true, F is prime.

3 0
3 years ago
If $x$ is the average of $13$, $-16$, and $6$ and if $y$ is the cube root of $8$, find $x^2 + y^3$. Please Help
Alekssandra [29.7K]

Answer:

If we have a set of N elements:

{x₁, x₂, ..., xₙ}

The mean value (also called the average value) Is calculated as:

Average = (x₁ + x₂ + ... + xₙ)/n

So if x is the average of 13, -16 and 6 ( a total of 3 values)

x will be equal to:

x = (13 + (-16) + 6)/3 = (19 - 16)/3 = 3/3 = 1

x = 1

And we know that:

y = ∛8

Remember that:

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and

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then

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then ∛8 = 2.

So we have:

y = ∛8 = 2

Now we can replace these values in the equation:

x^2 + y^3

replacing:

x = 1

y = 2

we get:

1^2 + 2^3 = 1 + 8 = 9

5 0
2 years ago
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