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boyakko [2]
3 years ago
5

There are 10 cups placed on a table face down. Beneath each cup is one coin. Together, there are 5 quarters, 2 nickels, and 3 di

mes. One cup is randomly selected, replaced, and then another cup is selected. What is the probability of getting a quarter then a nickel?
The options are
- 3/20
- 1/10
- 1/9
- 7/10
​

Mathematics
2 answers:
DedPeter [7]3 years ago
5 0

Answer:7/10

Step-by-step explanation:

Add the nickels and quarters together. 5+2=7

The sum of the two numbers is the answer out of ten because there are only 10 coins.

sweet-ann [11.9K]3 years ago
4 0

Answer:

1 / 10

Step-by-step explanation:

Prob of  getting a quarter on the first draw  =  (5/10)

Prob of getting a nickel on the second draw  = (2/10)

So......the overall probability  is   (5/10) (2/10)  =  10 / 100  =    1 / 10

Took the test and this is the correct answer

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The sum of the first 8 items in the geometric sequence:1, 3, 9, 27, ...etc is 3280.

Step-by-step explanation:

The given is,

            sequence: 1,3,9,21,.. etc

Step:1

           The given is based on multiplication of 3 to previous number,

           ( x - previous number, next number = 3 × x )

            First term : 1

            Second term : 1 × 3 = 3

           Third term : 3 × 3 = 9

            Fourth term : 9 × 3 =27

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            Eighth term : 729 × 3 = 2187

Step:2

            Sum of first 8 terms = 1 + 3 + 9 + 27 + 81 + 243 + 729 + 2187

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Result:

           The sum of the first 8 items in the geometric sequence:1, 3, 9, 27, ...etc is 3280.

                                       

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