There are 10 cups placed on a table face down. Beneath each cup is one coin. Together, there are 5 quarters, 2 nickels, and 3 di
mes. One cup is randomly selected, replaced, and then another cup is selected. What is the probability of getting a quarter then a nickel?
The options are
- 3/20
- 1/10
- 1/9
- 7/10
The options are
- 3/20
- 1/10
- 1/9
- 7/10
2 answers:
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Step-by-step explanation:
From your problem statement, I believe the equation will look like this:
The slash means "divided by" -- you should use division to solve this equation.
For division involving exponents with the same base, you can use the following rule:
Subtituting for
,
for
and
for
, we get the following: