All categories

2 years ago

Need help ASAP! Question in screenshot

Mathematics

2 answers:

Mashutka [201]2 years ago

4 0

Answer:

Step-by-step explanation:

uranmaximum [27]2 years ago

3 0

A Is the answer to the question

You might be interested in

herro help me .. .........................................................................................

skelet666 [1.2K]

So the easiest way to solve this is to use the straight line provided .
180=90+61+x
180=151+x
29=x

4 0

3 years ago

Read 2 more answers

The n candidates for a job have been ranked 1, 2, 3,…, n. Let X 5 the rank of a randomly selected candidate, so that X has pmf p

Anon25 [30]

Answer:

A. E(x) = 1/n×n(n+1)/2

B. E(x²) = 1/n

Step-by-step explanation:

The n candidates for a job have been ranked 1,2,3....n. Let x be the rank of a randomly selected candidate. Therefore, the PMF of X is given as

P(x) = {1/n, x = 1,2...n}

Therefore,

Expectation of X

E(x) = summation {xP(×)}

= summation {X×1/n}

= 1/n summation{x}

= 1/n×n(n+1)/2

= n+1/2

Thus, E(x) = 1/n×n(n+1)/2

Value of E(x²)

E(x²) = summation {x²P(×)}

= summation{x²×1/n}

= 1/n

3 0

3 years ago

The miles-per-gallon rating of passenger cars is a normally distributed random variable with a mean of 33.8 mpg and a standard d

EleoNora [17]

Answer:

The probability that a randomly selected passenger car gets more than 37.3 mpg is 0.1587.

Step-by-step explanation:

Let the random variable <em>X</em> represent the miles-per-gallon rating of passenger cars.

It is provided that $X\sim N(\mu=33.8,\ \sigma^{2}=3.5^{2})$ .

Compute the probability that a randomly selected passenger car gets more than 37.3 mpg as follows:

$P(X>37.3)=P(\frac{X-\mu}{\sigma}>\frac{37.3-33.8}{3.5})$

$=P(Z>1)\\\\=1-P(Z$

Thus, the probability that a randomly selected passenger car gets more than 37.3 mpg is 0.1587.

7 0

2 years ago

What is the scale factor of 5.8 and 1.45

Marianna [84]

No clue at all, Soorieee

4 0

3 years ago

Read 2 more answers

Triangle ABC has vertices A(-2,0), B(2,5), C(3, 1). The reflection of the image of triangle ABC is triangle A'B'C' with vertices

geniusboy [140]

Answer: Reflection about x-axis

Step-by-step explanation:

Given

Initially, vertices are $A(-2,0), B(2,5),C(3,1)$

After reflection they become $A(-2,0),B(2,-5),C(3,-1)$

It is clear that the x coordinate remains unchanged and the y coordinate changes its sign. It occurs when reflection is done about the x-axis.

For example, when (a,b) is reflected about the x-axis, it becomes (a,-b).

So, here reflection is being done about the x-axis.

4 0

3 years ago