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4 years ago

Choose the equation that represents the line passing through the point (2, - 5) with a slope of −3.

Mathematics

1 answer:

zzz [600]4 years ago

4 0

<h2>Answer:</h2>

We must determine the y-intercept, b using the slope and point provided.

$-5 = -3(2) + b\\\\-5 = -6 + b\\\\1 = b$

Now that we know the y-intercept, b, we can create the equation of this line: y = -3x + 1.

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A cylinder has a radius of 6 centimeters and a height of 18 centimeters. A smaller cylinder has linear dimensions that are one-t

vlabodo [156]

Answer:

the larger cyclinder has a surface area which is 9 times the surface area of the smaller cyclinder.

Step-by-step explanation:

Surface area of larger cyclinder

Radius = 6cm

Height = 18cm

A = 2πrh + 2πr^2

= 2*3.14*6*18 + 2*3.14*6^2

= 678.24 + 226.08

= 904.32 cm

Smaller cyclinder (1/3 of the larger cyclinder)

Radius = 2cm

Height = 6cm

A = 2πrh + 2πr^2

= 2*3.14*2*6 + 2*3.14*2^2

= 75.36 + 25.12

= 100.48 cm

Comparing the surface area of the larger cyclinder and the smaller cyclinder

= 904.32 cm / 100.48 cm

= 9

This means, the larger cyclinder has a surface area which is 9 times the surface area of the smaller cyclinder.

5 0

3 years ago

I dont get this pls help with steps asap!

kati45 [8]

Answer:

2.5

Step-by-step explanation:

it's the midpoint of XZ

7 0

3 years ago

Read 2 more answers

A park bench is located 73 1/2 feet away from the basketball court. The pond which is located between the two is 25 3/8 feet awa

grigory [225]

Answer:

The pond is located $48\frac{1}{8}\ feet$ away from the park bench.

Step-by-step explanation:

Given:

A park bench is located 73 1/2 feet away from the basketball court. The pond which is located between the two is 25 3/8 feet away from the basketball court.

Now, to find the distance the park bench from the pond.

The distance park bench is located away from the basketball court = $73\frac{1}{2}\ feet=\frac{147}{2} \ feet.$

As, the pond is located between the park bench and the basketball court.

The distance pond is located away from the basketball court = $25\frac{3}{8}=\frac{203}{8}\ feet.$

Now, to get the distance far away the pond is located from the park bench by subtracting the distance pond is located away from the basketball court from the distance park bench is located away from the basketball court:

$\frac{147}{2}-\frac{203}{8}$