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gogolik [260]
2 years ago
13

Solve forx A-15° B-75° C-90° D-165°

Mathematics
2 answers:
SIZIF [17.4K]2 years ago
8 0

Answer:

10.94 triangle

Step-by-step explanation:

Softa [21]2 years ago
6 0
75° because a right angle is 90 degrees so, 90-15=75
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Select the graph for the solution of the open sentence. Click until the correct graph appears. |x| > 3/2
Soloha48 [4]
ANSWER

See attachment

EXPLANATION

The given inequality is

|x| \: > \: \frac{3}{2}

This implies that,

x\: > \: \frac{3}{2} \: or \: - x\: > \: \frac{3}{2}

Multiply both sides of the second inequality by -1 and reverse the inequality sign.

x\: > \: \frac{3}{2} \: or \: x\: < \: - \frac{3}{2}

The graphical solution to this inequality is shown in the attachment.

7 0
3 years ago
Find the value of x.<br> When a leg is 6<br> units and the<br> hypotenuse is 12<br> units.
DIA [1.3K]

Answer:

6√3

Step-by-step explanation:

6^2+x^2=12^2

36+x^2=144

-36          -36

x^2=108

x=6√3

3 0
3 years ago
What is the measure for angle CBD <br> PLSSS HELPP!!!!​
Andrei [34K]

The measure of the angle CBD = 180° - 30° = 150°.

3 0
3 years ago
Sushilis now 4 times as old as Sunil. 5 years ago Sushilwas 7 times as old as Sunil was then. Find the present ages of each of t
Illusion [34]

Answer:

Sunil = 10 and Sushil= 40

Step-by-step explanation:

Present ages-

Sushil= 4x

Sunil= x

5 years ago-

Sushil = 4x - 5

Sunil = x - 5

4x - 5 = 7(x - 5) = 4x - 5 = 7x - 35

                        = -5 = 3x - 35

                        = 30 = 3x

                        = 10 = x

So substitute the xs for 10-

Present Sushil= 4 x 10 = 40

Present Sunil= 10

6 0
3 years ago
The 3rd and 6th term of a geometric progression are 9/2 and 243/16 respectively find the first term, common ratio, seventh term​
sashaice [31]

Answer:

Hello,

Step-by-step explanation:

Let\ (u_n)\ the\ geometric\ progression.\\\\r\ is\ the\ common\ ratio.\\\\u_3=u_0*r^3\\u_6=u_0*r^6\\\\\dfrac{u_6}{u_3} =r^3=\dfrac{\frac{243}{16} }{\frac{9}{2} } =\dfrac{27}{8} =(\frac{3}{2} )^3\\\\\boxed{r=\dfrac{3}{2} }\\\\\\u_3=u_1*r^2 \Longrightarrow\ u_1=\dfrac{u_3}{r^2} =\dfrac{\frac{9}{2} }{(\frac{3}{2^2}) } =2\\\\\\u_7=u_6*\dfrac{3}{2} =\dfrac{729}{32}

5 0
3 years ago
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