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3 years ago

2. Triangle ABC and triangle EFD ARE ?PLEASE HELP

Mathematics

1 answer:

ad-work [718]3 years ago

3 0

Answer:

similar SAS

Step-by-step explanation:

because the angle c has the angle c and sides are cb,ba .

because the angle d has the angle d and slide are df, Fe

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He can use three bookshelves. there will be 3 math books on each of the three shelves and 2 reading books on each of the shelves. 3 is the greatest common factor of 9 and 6.

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3 years ago

What is the mean absolute deviation 3,5,8,1,4

erastovalidia [21]

Answer:

the mean is 4.2

Step-by-step explanation:

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3 years ago

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Your city is having a sneaker convention! A pair of Ground Morgans is 20% less expensive than a pair of Elite Butterflies, Elite

Amanda [17]

Answer:

Ground Morgans are 52% the price of Floating Jumps.

Step-by-step explanation:

A pair of Ground Morgans $GM$ is 20% less expensive than a pair of Elite Butterflies $EB$ , this means

$GM= 0.8 EB$ (GM is 80% the price of EB's)

Elite Butterflies $EB$ are 30% more expensive than Cloud Trainers $CT$ 's, this means

$EB =1.3 CT$ (EM's is 130% the price of CT's)

Cloud Trainers $CT$ are 50% less expensive than Floating Jumps $FJ$ , this means

$CT=0.5FJ$ (CT is 50% the price of FJ)

Now, if we want the price of Ground Morgans in terms of Floating Jumps, then, since EB = 1.3 CT,

$GM=0.8 (1.3CT)$

and since CT = 0.5F, we have

$GM = 0.8(1.3(0.5FJ))$ .

Simplifying we get

$\boxed{GM =0.52FJ}$

Ground Morgans are 52% the price of Floating Jumps.

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3 years ago

Mrs. Drake gave her class the following problem to solve

Triss [41]

Answer:

Kylie is incorect the aswer is supposed to be 32

Step-by-step explanation:

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3 years ago

H=vt+1/2gt^2 solving for G GIVING BRAINLISEST

ololo11 [35]

Answer:

$g=\frac{2h}{t^2}-\frac{2v}{t}$

Step-by-step explanation:

So we have the equation:

$h=vt+\frac{1}{2}gt^2$

And we want to solve for g.

First, isolate g. To do so, subtract vt from both sides:

$h-vt=\frac{1}{2}gt^2$

Multiply both sides by 2:

$2h-2vt=gt^2$

Now, divide both sides by t^2:

$g=\frac{2h-2vt}{t^2}$

Expand:

$g=\frac{2h}{t^2}-\frac{2vt}{t^2}$

Simplify the second term:

$g=\frac{2h}{t^2}-\frac{2v}{t}$

And we're done!

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3 years ago

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