Ava is thinking of a four-digit number described below.
2 answers:
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Answer:
<h2>There are 13 quarters, 5 nickels and 20 dimes.</h2>Step-by-step explanation:
Givens
- Max has $5.50.
- He has eight more quarters than he does nickels.
- He had four times as many dimes as he has nickels.
From these statements, we can deduce algebraical expressions to solve the problem. Let's call quarters,
nickels and
dimes.
(8 more quarters than nickels)
(he has four times as many dimes as he has nickels).
(Max has a total of $5.50, one quartes is $0.25, one nickel is $0.05 and one dime is $0.10).
Let's replace the first two expressions into the third equation
There are 5 nickels.
Now, we use this value to find the number of quarters
There are 13 quarters.
Also,
There are 20 dimes.
Therefore, there are 13 quarters, 5 nickels and 20 dimes.
1/7p = 3
Multiple both sides by 7
7 x 1/7p = 7 x 3
Then cross multiply
P= 21
Multiple both sides by 7
7 x 1/7p = 7 x 3
Then cross multiply
P= 21