Step-by-step explanation:
step 1. This is a right triangle where a^2 + b^2 = c^2 (c is the hypotenuse).
step 2. a^2 + 6^2 = 8^2.
step 3. a^2 = 64 - 36.
step 4. a^2 = 28.
step 5. a (the ladder height along the wall) = sqrt (28) where sqrt is the square root.
<u>step</u><u> </u><u>6</u><u>.</u><u> </u><u>sqrt</u><u>(</u><u>2</u><u>8</u><u>)</u><u> </u><u>=</u><u> </u><u>2</u><u>(</u><u>sqrt</u><u>(</u><u>7</u><u>)</u><u>)</u><u>.</u>
Answer:
Step-by-step explanation:
![\sqrt[3]{54c}=\sqrt[3]{3*3*3*2c} =3\sqrt[3]{2c}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B54c%7D%3D%5Csqrt%5B3%5D%7B3%2A3%2A3%2A2c%7D%20%3D3%5Csqrt%5B3%5D%7B2c%7D)
Answer:
16
Step-by-step explanation:
The common ratio is 36/54 = 2/3.
So the next term is 2/3 (24) = 16.
Answer:
100
Step-by-step explanation:
With amounts measured in gallons, let
x = amount of 65% antifreeze
y = amount of 90% antifreeze
1 gal of the 65% brand contains 0.65 gal of pure antifreeze; x gal would contain 0.65x gal. Similarly, y gal of the 90% brand contains 0.90y gal of pure antifreeze.
To obtain 120 gal of 80% antifreeze solution (which contains 0.80•120 = 96 gal of pure antifreeze), we must have
x + y = 120 … … … … … [total volume of antifreeze solution]
0.65x + 0.90y = 96 … [total volume of pure antifreeze]
Solve the first equation for y :
y = 120 - x
Substitute this into the second equation and solve for x :
0.65x + 0.90 (120 - x) = 96
0.65x + 108 - 0.90x = 96
0.25x = 12
x = 48
Solve for y :
y = 120 - 48
y = 72