Question

If x + y =6, y +z = 7 and z + x =9, what is the average (arithmetic mean) of x,y and z?

Answer 1

Answer:

$\frac{22}{3}$

Step-by-step explanation:

x + y + y + z + z + x = 2x + 2y + 2z = 22

x + y + z = 22

22 ÷ 3 = $\frac{22}{3}$