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blondinia [14]
3 years ago
6

If x + y =6, y +z = 7 and z + x =9, what is the average (arithmetic mean) of x,y and z?

Mathematics
1 answer:
nadya68 [22]3 years ago
8 0

Answer:

\frac{22}{3}

Step-by-step explanation:

x + y + y + z + z + x = 2x + 2y + 2z = 22

x + y + z = 22

22 ÷ 3 = \frac{22}{3}

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Suppose that 16% of people have a dog. 32% of people have a cat, and 10% of people own both. What is the probability that someon
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Step-by-step explanation:

Let the even that a person has a dog be A. The probability is given 16% this implies:

<em>P(A)</em> = 0.16 ..... (1)

Let the event that a person has a cat denote by B. The probability of B is given to be 32% this implies....  

<em>P(B</em>) = 0.32 ..... (2)

Then the event that a person has a dog and a cat will be denoted by A∩B. The probability of A∩B is given to be 10%: This implies:

<em>P(A∩B= = 0.12 .......(3)</em>

The event that someone owns a cat and a dog will denoted by the event <em>A∪B.</em> It is observed that A and B are not disjoint. This implies that the probability of this event is depicted as:

<em>P(A∪B) = P (A) + P(B) - P(A∩B)</em>

Substitute (1) , (2) and (3), in the above, we get:

<em>P(A∪B) = 0.16 + 0.32 - 0.10 = 0.38</em>

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