3(x-1)=2x + 9<br> Don’t really understand how to do this

A regular polygon has an odd number of sides. Which statement is true about the lines of reflection for the polygon that will ma

Novosadov [1.4K]

Answer:

The only correct option is:

Option B. The perpendicular bisectors for each side are the only lines of reflection.

Step-by-step explanation:

A regular polygon has an odd number of sides. Which statement is true about the lines of reflection for the polygon that will map the shape onto itself?

A.

Lines that connect pairs of opposite vertices are lines of reflection.

B.

The perpendicular bisectors for each side are the only lines of reflection.

C.

The lines of reflection are parallel to the sides of the polygon.

D.

There are no lines of reflection.

The only correct option is:

Option B. The perpendicular bisectors for each side are the only lines of reflection.

6 0

3 years ago

Oli's stuffed bear shop has 456 bears in stock. Exactly half of them are made from wool. What is the divisor

algol [13]

Ummm... I Think U Just Have To Do: 456-100 (OR) 456-200.

3 0

3 years ago

Read 2 more answers

Modeling Radioactive Decay In Exercise, complete the table for each radioactive isotope.

Travka [436]

Answer :

The amount after 1000 years will be, 5.19 grams.

The amount after 10000 years will be, 0.105 grams.

Step-by-step explanation :

Half-life = 1599 years

First we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{1599\text{ years}}$

$k=4.33\times 10^{-4}\text{ years}^{-1}$

Now we have to calculate the amount after 1000 years.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $4.33\times 10^{-4}\text{ years}^{-1}$

t = time passed by the sample = 1000 years

a = initial amount of the reactant = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

$1000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}$

$a-x=5.19g$

Thus, the amount after 1000 years will be, 5.19 grams.

Now we have to calculate the amount after 10000 years.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $4.33\times 10^{-4}\text{ years}^{-1}$

t = time passed by the sample = 10000 years

a = initial amount of the reactant = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

$10000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}$

$a-x=0.105g$

Thus, the amount after 10000 years will be, 0.105 grams.

4 0

3 years ago

PLEASE HELP ME I WILL MARK YOU BRAINLIEST FOR THIS ANY ANSWERS!!!)Mr. Perez designs a probability model to help him predict whic

Nesterboy [21]

Answer:

Number A. is True. B. is False. C. is IDK D. is False. E. is true.

Step-by-step explanation:

If you read it you can tell plus I broke it down and solved it on paper.

6 0

3 years ago

Read 2 more answers

Two numbers, a and b, are stored in one byte floating point notation using the least significant (rightmost) 3 bits for the expo

ehidna [41]

$a=00110111 = 00110_2 \times 2^{111_2} = 6 \times 2^{-1} = 3$

$b=11011000 = 11011_2 \times 2^{000_2} = -(0100_2 + 1) =-(4+1)=-5$

$a+b=-2 = -1 \times 2^{001} = -2 \times 2^{0} = -4 \times 2^{-1}$ etc.

$a+b=-2 = 11111001 = 11110000 = 11100111 = ...$

Hard to select the correct answers without seeing the choices. Let's check a couple,

$11111001 = -(00000+1) \times 2^{1} = -2 \quad\checkmark$

$11110000 = -(00001 + 1) \times 2^{0} = -2 \quad\checkmark$

$11100111 = -(00011 + 1) \times 2^{-1} = -4/2= -2 \quad\checkmark$

4 0

3 years ago

3(x-1)=2x + 9 Don’t really understand how to do this