Answer/Explanation:
It is best to use Performance Monitor and Process counters to observe performance.
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The development of new information system is economically justified when or if the organization or group handling the information system has assessed its cost feasibility. If so, this will only fall under the circumstances that the information system is justified economically
Answer:
In the time complexity, the array-list can easily be accessible any type of element in the the given list in the fixed amount of time.
On the other hand, the linked list basically require that the list must be traversed from one position to another end position.
The Array-List can get to any component of the rundown in a similar measure of time if the file value is know, while the Linked-List requires the rundown to be crossed from one end or the other to arrive at a position.
Answer:
The program is written using PYTHON SCRIPT below;
N=int(input(" Enter number of Rows you want:"))
M=[] # this for storing the matrix
for i in range(N):
l=list(map(int,input("Enter the "+str(i+1)+" Row :").split()))
M.append(l)
print("The 2D Matrix is:\n")
for i in range(N):
print(end="\t")
print(M[i])
W=[] # to store the first non zero elemnt index
T=[] # to store that value is positive or negative
L=len(M[0])
for i in range(N):
for j in range(L):
if (M[i][j]==0):
continue
else:
W.append(j) # If the value is non zero append that postion to position list(W)
if(M[i][j]>0): #For checking it is positive or negative
T.append(+1)
else:
T.append(-1)
break
print()
print("The first Non Zero element List [W] : ",end="")
print(W)
print("Positive or Negative List [T] : ",end="")
print(T)
Explanation:
In order for the program to determine a set of test cases it takes in input of 2D matrix in an N numbet of rows.
It goes ahead to program and find the column index of the first non-zero value for each row in the matrix A, and also determines if that non-zero value is positive or negative. The If - Else conditions are met accordingly in running the program.
