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3 years ago

Tommy throws a ball from the balcony of his apartment down to the street. The

Mathematics

2 answers:

anygoal [31]3 years ago

6 0

Answer: c

Step-by-step explanation:

Nesterboy [21]3 years ago

5 0

Answer:

Step-by-step explanation:

got it right on the test

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Angles ABC and DBE are vertical angles, with angle ABC = 4x, and angle DBE =( 2x+18)

Dmitrij [34]

V<span>ertical angles are equal.
We have 4x = 2x + 18.
Then, 2x = 18;
x = 18 </span>÷ 2;
x = 9 degrees;
The measure of angle DBE is 2 × 9 + 18 = 36 degrees.

3 0

3 years ago

Use a number line to solve 5+7

Neporo4naja [7]

To start off, 5+7=12, so we already know how the number line will be laid out. We will have Point A on 5, and count up 7 units, plotting Point B on 12.

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3 years ago

Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE

EleoNora [17]

Answer:

0, 10

Step-by-step explanation:

The given function is:

$g(y) = \frac{y-5}{y^2-3y+15}$

According to the quotient rule:

$d(\frac{f(y)}{h(y)}) = \frac{f(y)*h'(y)-h(y)*f'(y)}{h^2(y)}$

Applying the quotient rule:

$g(y) = \frac{y-5}{y^2-3y+15}\\g'(y)=\frac{(y-5)*(2y-3)-(y^2-3y+15)*(1)}{(y^2-3y+15)^2}$

The values for which g'(y) are zero are the critical points:

$g'(y)=0=\frac{(y-5)*(2y-3)-(y^2-3y+15)*(1)}{(y^2-3y+15)^2}\\(y-5)*(2y-3)-(y^2-3y+15)=0\\2y^2-3y-10y+15-y^2+3y-15\\y^2-10y=0\\y=\frac{10\pm \sqrt 100}{2}\\y_1=\frac{10-10}{2}= 0\\y_2=\frac{10+10}{2}=10$

The critical values are y = 0 and y = 10.

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3 years ago

Estimate to the nearest tenth.<br><br> negative square root 93

liberstina [14]

I think it would be -9.64

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3 years ago

I need help I don’t get this at all

dolphi86 [110]

Answer:

Step-by-step explanation:

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3 years ago