Let the original length of the square be x cm.
(x+5) X (x-2) = 60
Or, x^2-2x+5x-10-60 = 0
Or, x^2+3x-70=0
Or, x^2+10x-7x-70=0
Or, x(x+10)-7(x+10)=0
Or, (x-7)(x+10)=0
Therefore, x=7 or x=-10 (rejected as the length cannot be negative)
Ans: Area of the square=l^2=7^2=49 square meters.

4 0

3 years ago

Find a gradient of a line that is parallel and perpendicular to this line with this gradient of -2

yulyashka [42]

a gradient of a line that is parallel and perpendicular to this line with this gradient of -2

Gradient is the slope

So slope of the line =-2

Slope of parallel line is equal to the slope of the line

So slope of parallel line = -2

Slope of perpendicular line is equal to negative reciprocal of slope of the line

We know slope of line = -2

Negative reciprocal = $\frac{1}{2}$

So , Slope of perpendicular line= $\frac{1}{2}$

7 0

3 years ago

True or false:

Alinara [238K]

1.true
2.true
3.because it supposed to be 4 sides like a rhombus
I’m not sure if they are right

8 0

4 years ago