Answer:
2(3x + 1)(x + 1)
Step-by-step explanation:
Given
6x² + 8x + 2 ← factor out 2 from each term
= 2(3x² + 4x + 1) ← factor the quadratic
Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term
product = 3 × 1 = 3 and sum = 4
The factors are + 3 and + 1
Use these factors to split the x- term
3x² + 3x + x + 1 ( factor the first/second and third/fourth terms )
= 3x(x + 1) + 1(x + 1) ← factor out (x + 1) from each term
= (3x + 1)(x + 1) , then
3x² + 4x + 1 = (3x + 1)(x + 1)
and
6x² + 8x + 2 = 2(3x + 1)(x + 1) ← in factored form