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3 years ago

Select all of the symbols that would make the comparison true.

Mathematics

2 answers:

Elis [28]3 years ago

8 0

Step-by-step explanation:

- |-9| = -9

So, -|-9| = -9

Good luck

Ilya [14]3 years ago

8 0

Answer:

last number option is correct

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An airplane flies due north from ikeja airport for 500km.It then flies on a bearing of 060 from a further distance of 300km befo

Nata [24]

Answer:

482 km

63.94 degrees

Step-by-step explanation:

to solve this question we will use the cosine rule. For starters, draw your diagram. From point A, up north is 500km and 060 from there, another 300. If you join the point from the road junction back to the starting point, yoou have a triangle.

Cosine rule states that

C = $\sqrt{A^{2} + B^{2} -2AB cos(c) }$

where both A and B are the given distances, 500 and 300 respectively, C is the 3rd distance we're looking for and c is the given angle, 060

solving now, we have

C = $\sqrt{500^{2} + 300^{2} -2 * 500 * 300 cos(60) }$

C = $\sqrt{250000 + 90000 - [215000 cos(60) }]$

C = $\sqrt{340000 - [215000 * 0.5 }]$

C = $\sqrt{340000 - [107500 }]$

C = $\sqrt{232500}$

C = 482 km

The bearing can be gotten by using the Sine Rule.

$\frac{sina}{A}$ = $\frac{sinc}{C}$

sina/500 = sin60/482

482 sina = 500 sin60

sina = $\frac{500 sin60}{482}$

sina = 0.8983

a = sin^-1(0.8983)

a = 63.94 degrees

6 0

3 years ago

Suppose a line has slope 4 and passes through the point (-2,5). Which other point must also be on the graph?

xxMikexx [17]

Slope of 4 means you add 4 to the y and 1 to the x so the answer is (-1,9)

5 0

3 years ago

Find the value of x?

densk [106]

Answer:

x = 6 7/9

Step-by-step explanation:

Any triangle inscribed in a circle with one side being a diameter is a right triangle.

9x - 14 = 180 - 90 - 43

9x - 14° = 47°

9x = 61°

x = 6 7/9

7 0

3 years ago

Solve for x.<br> 79<br> (8x - 4)<br> 3<br> -(3x + 17)

Liono4ka [1.6K]

Answer:

-2.4

Step-by-step explanation:

maybe... i am 99.99% sure

6 0

3 years ago

Alexandra invested $800 in an account paying an interest rate3.1% compounded continuously. Assuming no deposits or withdrawals a

s2008m [1.1K]

$\bf ~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$800\\ r=rate\to 3.1\%\to \frac{3.1}{100}\dotfill &0.031\\ t=years\dotfill &20 \end{cases} \\\\\\ A=800e^{0.031\cdot 20}\implies A=800e^{0.62} \\\\\\ A\approx 1487.14\implies A=\stackrel{rounded~up}{1500}$

8 0

4 years ago