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tia_tia [17]
2 years ago
8

Evaluate the following equation for p: -3p + 6 + 7p = 22

Mathematics
2 answers:
strojnjashka [21]2 years ago
5 0

Answer:

4

Step-by-step explanation:

-3p+6+7p=22

-3p+7p=16

4p=16

p=4

mart [117]2 years ago
5 0

Answer:

p = 4

Step-by-step explanation:

-3p+6+7p = 22

     -6         -6

----------------------

-3p+7p = 16

4p = 16

---     ---

4       4

------------

p = 4

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Select the indicated real nth root(s) of a.<br> n=3, a = 64
arsen [322]

9514 1404 393

Answer:

  4

Step-by-step explanation:

∛64 = ∛(4³) = 4

_____

The real root when the root index is odd will have the same sign as the value whose root it is. 64 is positive, so the real cube root will be positive.

5 0
3 years ago
Will give brainliest amswer ❤️
Fiesta28 [93]

Answer:

78.5 square units

Step-by-step explanation:

d = 10 \implies \: r =  \frac{10}{2} = 5 \\ area \: of \: circle \\= \pi {r}^{2}   \\  = 3.14 \times  {5}^{2}  \\  = 3.14 \times 25 \\  = 78.5  \:  {units}^{2} \\

8 0
3 years ago
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Math problem. I need help plz.
mash [69]

Answer:

Never because one of them goes 1k8 and one of them goes 24 so if they that song every time then it would be the same time diffrence even if you try a million tinmes

Step-by-step explanation:

6 0
2 years ago
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Devaughn's age is three times Sydney's age. The sum of their ages is 52. What is Sydney's age?
Alborosie

Answer:

Sydney is 13 and Devaughn is 39

Step-by-step explanation:

13x3=39

39+13=52

8 0
3 years ago
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a. Fill in the midpoint of each class in the column provided. b. Enter the midpoints in L1 and the frequencies in L2, and use 1-
Tresset [83]

Answer:

\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1}  & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7}  & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}

Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795

Step-by-step explanation:

Given

See attachment for class

Solving (a): Fill the midpoint of each class.

Midpoint (M) is calculated as:

M = \frac{1}{2}(Lower + Upper)

Where

Lower \to Lower class interval

Upper \to Upper class interval

So, we have:

Class 63-65:

M = \frac{1}{2}(63 + 65) = 64

Class 66 - 68:

M = \frac{1}{2}(66 + 68) = 67

When the computation is completed, the frequency distribution will be:

\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1}  & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7}  & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}

Solving (b): Mean and standard deviation using 1-VarStats

Using 1-VarStats, the solution is:

\bar x = 70.2903

\sigma = 3.5795

<em>See attachment for result of 1-VarStats</em>

8 0
3 years ago
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