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HACTEHA [7]
2 years ago
12

Write the equation of the line in slope intercept form that goes through points (-2, 5) and (3, 3)

Mathematics
1 answer:
Jobisdone [24]2 years ago
8 0

Answer:

y=-2/5x+21/5

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(3-5)/(3-(-2))

m=-2/(3+2)

m=-2/5

y-y1=m(x-x1)

y-5=-2/5(x-(-2))

y-5=-2/5(x+2)

y=-2/5x-4/5+5

y=-2/5x-4/5+25/5

y=-2/5x+21/5

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Round up 395,621 to the nearest ten thousand
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396,000
because 5 goes up and anything lower than five stays the same
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3 years ago
Turn 2 1/2 into a percentage
saw5 [17]

Answer:

250%

Step-by-step explanation:

(2 1/2) × 100%

= 250%

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5 0
2 years ago
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We are standing on the top of a 320 foot tall building and launch a small object upward. The object's vertical altitude, measure
STALIN [3.7K]

Answer:

The highest altitude that the object reaches is 576 feet.

Step-by-step explanation:

The maximum altitude reached by the object can be found by using the first and second derivatives of the given function. (First and Second Derivative Tests). Let be h(t) = -16\cdot t^{2} + 128\cdot t + 320, the first and second derivatives are, respectively:

First Derivative

h'(t) = -32\cdot t +128

Second Derivative

h''(t) = -32

Then, the First and Second Derivative Test can be performed as follows. Let equalize the first derivative to zero and solve the resultant expression:

-32\cdot t +128 = 0

t = \frac{128}{32}\,s

t = 4\,s (Critical value)

The second derivative of the second-order polynomial presented above is a constant function and a negative number, which means that critical values leads to an absolute maximum, that is, the highest altitude reached by the object. Then, let is evaluate the function at the critical value:

h(4\,s) = -16\cdot (4\,s)^{2}+128\cdot (4\,s) +320

h(4\,s) = 576\,ft

The highest altitude that the object reaches is 576 feet.

6 0
3 years ago
Solve for x and y
bekas [8.4K]

Answer:

x = 2√2

y = 2√6

Step-by-step explanation:

Consider the ratio of the two legs of the two smaller interior right triangles. (refer to attached diagrams for the triangles - I have outlined one in blue and the other in red)

These will be equal since the triangles are similar

shorter leg : longer leg

(blue triangle = red triangle)

⇒ x : 4 = 2 : x

⇒ x/4 = 2/x

⇒ x² = 8

⇒ x = √8

⇒ x = 2√2

Now we have x, we have the two legs of the right triangle with hypotenuse labelled y.

Using Pythagoras' Theorem a² + b² = c² (where a and b are the legs and c is the hypotenuse)

⇒ 4² + (2√2)² = y²

⇒ y² = 24

⇒ y = √24

⇒ y = 2√6

7 0
2 years ago
PLZ HELP
Sergio039 [100]

Answer:

Step-by-step explanation:

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2 years ago
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