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gogolik [260]
3 years ago
8

Which set of shapes can be arranged in 6 equal groups, with no shapes left over?

Mathematics
1 answer:
nasty-shy [4]3 years ago
5 0
Is there supposed to be a picture??
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Two sides of a triangle have the same length. The third side measures 6 m less than twice the common length. The perimeter of th
Lostsunrise [7]

Let x be the common length. Then, the sides of the triangle are x, x, and 2x-6. These three sides sum up to 22, so you have

x+x+2x-6 = 22 \iff 4x = 28 \iff x = 7

So, the two equal sides are 7m long, and the third side is

2\cdot 7 - 6 = 14 - 6 = 8

8 0
3 years ago
(8,15) (-14,-3)<br>find the slope
ss7ja [257]

The slope is 9/11 because if you use the formula (change in y)/(change in x), you would get -18/-22 and then if it were to be simplified, it would be 9/11

5 0
3 years ago
The physician orders 1500 flu injections. There were 300 shots given in September, 450 shots given in October, and 665 shots giv
lions [1.4K]

Answer:

50%

Step-by-step explanation:

You take the 1500 shots and take away the 300 and 450 you get 750 you divide 750 from 1500 then you get 0.5 and you multiply it with 100 and you get the answer 50.

8 0
3 years ago
Read 2 more answers
Shureka Washburn has scores of 67​, 68​, 76​, and 63 on her algebra tests. a. Use an inequality to find the scores she must make
mash [69]
Average=(total number)/(number of items)
given that the final exam counts as two test, let the final exam be x. The weight of the final exams on the average is 2, thus the final exam can be written as 2x because any score Shureka gets will be doubled before the averaging.
Hence our inequality will be as follows:
(67+68+76+63+2x)/6≥71
(274+2x)/6≥71
solving the above we get:
274+2x≥71×6
274+2x≥426
2x≥426-274
2x≥152
x≥76

b] The above answer is x≥76, the mean of this is that if Shureka is aiming at getting an average of 71 or above, then she should be able to get a minimum score of 76 or above. Anything less than 76 will drop her average lower than 71.


8 0
3 years ago
Suppose that a bluebird has a .65 probability of surviving to adulthood . If nest has 8 eggs what is the probability that of the
cluponka [151]
8x.65= 5.2 I haven’t learned this but I’m trying my best to or maybe it will be 8+.65 which will be 8.65 which is close to 9

8 0
3 years ago
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