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Vikentia [17]
3 years ago
11

If a line through the origin has a slope of 2, what is the slope of the line through the origin that is perpendicular to

Mathematics
1 answer:
Dmitriy789 [7]3 years ago
6 0

Answer:

-\frac{1}{2}

Step-by-step explanation:

We have the slope value of the first line, we will call this m_{1}

so  m_{1}=2

And we use the <u>condition </u>so that two lines are perpendicular: the product of the two slopes must be equal to -1.

That is, if the slope of the first line is m_{1} and the slope of the second line is m_{2}:

m_{1*}m_{2}=-1

we know that m_{1}=2, so:

2m_{2}=-1

and clearing for m_{2}:

m_{2}=-\frac{1}{2}

the slope of the line perpendicular to the line with a slope of 2 is: -\frac{1}{2}

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This question is essentially telling you to move the point (5, -2) over three units, and up four units. That means subtract three units from the x-coordinate and add four units to the y-coordinate. So (5 - 3, -2 + 4) --> (2, 2). The coordinates for the new point are (2, 2).
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25/35 = .71 = 71%

Step-by-step explanation:

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2 years ago
There are 10 employees in a particular division of a company. Their salaries have a mean of 570,000, a median of $55,000,and a s
harkovskaia [24]

Answer:

a) $160,000

b) $55,000

c) $332264.804

Step-by-step explanation:

We are given that there are 10 employees in a particular division of a company and their salaries have a mean of $70,000, a median of $55,000, and a standard deviation of $20,000.

And also the largest number on the list is $100,000 but By accident, this number is changed to $1,000,000.

a) Value of mean after the change in value is given by;

     Original Mean = $70,000

       \frac{\sum X}{n} = $70,000  ⇒ \sum X = 70,000 * 10 = $700,000

   New \sum X after change = $700,000 - $100,000 + $1,000,000 = $1600000

  Therefore, New mean = \frac{1600000}{10} = $160,000 .

b) Median will not get affected as median is the middle most value in the data set and since $1,000,000 is considered to be an outlier so median remain unchanged at $55,000 .

c) Original Variance = 20000^{2} i.e.  20000^{2} = \frac{\sum x^{2} - n*xbar }{n -1}

    Original \sum x^{2} = (20000^{2} * (10-1)) + (10 * 70,000) = $3,600,700,000

    New \sum x^{2} = $3,600,700,000 - 100,000^{2} + 1,000,000^{2} = 9.936007 * 10^{11}  

    New Variance = \frac{new\sum x^{2} - n*new xbar }{n -1} = \frac{9.936007 *10^{11}  - 10*160000 }{10 -1} = 1.103999 * 10^{11}    Therefore, standard deviation after change = \sqrt{1.103999 * 10^{11} } = $332264.804 .

7 0
3 years ago
Sabrina reads 15 pages per hour. She needs to finish a book with 120 pages. Which equation would you use to determine how many h
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Answer:

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Step-by-step explanation:

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3 years ago
How would you solve this? help.
Eddi Din [679]

Answer:

<em>Center: (3,3)</em>

<em>Radius: </em>2\sqrt{5}<em />

Step-by-step explanation:

<u>Midpoint and Distance Between two Points</u>

Given two points A(x1,y1) and B(x2,y2), the midpoint M(xm,ym) between A and B has the following coordinates:

\displaystyle x_m=\frac{x_1+x_2}{2}

\displaystyle y_m=\frac{y_1+y_2}{2}

The distance between both points is given by:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Point (5,7) is the center of circle A, and point (1,-1) is the center of the circle B. Given both points belong to circle C, the center of C must be the midpoint from A to B:

\displaystyle x_m=\frac{5+1}{2}=\frac{6}{2}=3

\displaystyle y_m=\frac{7-1}{2}=\frac{6}{2}=3

Center of circle C: (3,3)

The radius of C is half the distance between A and B:

d=\sqrt{(1-5)^2+(-1-7)^2}

d=\sqrt{16+64}=\sqrt{80}=\sqrt{16*5}=4\sqrt{5}

The radius of C is d/2:

r =4\sqrt{5}/2 = 2\sqrt{5}

Center: (3,3)

Radius: 2\sqrt{5}

8 0
3 years ago
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