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Vikentia [17]
3 years ago
11

If a line through the origin has a slope of 2, what is the slope of the line through the origin that is perpendicular to

Mathematics
1 answer:
Dmitriy789 [7]3 years ago
6 0

Answer:

-\frac{1}{2}

Step-by-step explanation:

We have the slope value of the first line, we will call this m_{1}

so  m_{1}=2

And we use the <u>condition </u>so that two lines are perpendicular: the product of the two slopes must be equal to -1.

That is, if the slope of the first line is m_{1} and the slope of the second line is m_{2}:

m_{1*}m_{2}=-1

we know that m_{1}=2, so:

2m_{2}=-1

and clearing for m_{2}:

m_{2}=-\frac{1}{2}

the slope of the line perpendicular to the line with a slope of 2 is: -\frac{1}{2}

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109 2/3 divided by 1/2​
Alexandra [31]

Answer:

\large\boxed{219\dfrac{1}{3}}

Step-by-step explanation:

109\dfrac{2}{3}:\dfrac{1}{2}\\\\\text{Divide by a fraction is the same operation as multiply by its reciprocal}\\\\109\dfrac{2}{3}:\dfrac{1}{2}=109\dfrac{2}{3}\cdot\dfrac{2}{1}=109\dfrac{2}{3}\cdot2=\left(109+\dfrac{2}{3}\right)\cdot2\\\\\text{use distributive property}\\\\(109)(2)+\left(\dfrac{2}{3}\right)(2)=218+\dfrac{4}{3}=218+1\dfrac{1}{3}=219\dfrac{1}{3}

3 0
3 years ago
What is m∠AEB?<br><br> m∠AEB? = ?
Jobisdone [24]
Ok so remember
when 2 lines intersect the 2 opposite angles that face each other are equal measure
also, remember that a straight line=180

so

therefor BEA=CED and we want to find BEA, also
BED=180 so
BEC+CED=BED=180
aka
6x+7+5x-3=180
solve

6x+7+5x-3=180
combine
11x+4=180
subttract 4
11x=176
diivde 11
x=16

CED=AEB
CED=5x-3
subsitute
CED=5(16)-3
CED=80-3
CED=77
CED=77=AEB


answer is 77 degreees
6 0
3 years ago
Solve 4 h = 92 for h
insens350 [35]

Answer:

Step-by-step explanation:

4h/4=92/4

h=23.

thx.

6 0
3 years ago
Read 2 more answers
Help with this work pls​
Travka [436]

Answer:

  (6, 2), (0, -2), (-3, -4)

Step-by-step explanation:

The intercepts are clearly (0, -2) and (3, 0). This eliminates the bottom two choices.

Both of these are listed in the upper left choice, but the third point there, (-6, -5), is not on the graph. This leaves only the upper right choice. Checking the remaining two points in that choice, (6, 2) and (-3, -4), confirms they are both on the graph.

8 0
3 years ago
Help me solve this question: 2/3(5q+2+6r)
djverab [1.8K]

Answer:

mommy harder yes pls ugHhH

4 0
2 years ago
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