Question

An original oil painting measures 55" x 55". The artist wants to produce prints that are 2.5 times smaller than the original painting. What will be the side length, in inches, of the prints?

Answer 1

Answer:

The side length of the prints is approximately 34.785 inches.

Step-by-step explanation:

First, we have to calculate the area of the original oil painting ($A$), measured in square inches, by the following formula:

$A = l^{2}$ (1)

Where $l$ is the length of the side, measured in inches.

And the length of the miniature is determine by means of reduction factor ($k$), with no unit:

$\frac{A}{k} = l'^{2}$ (2)

If we know that $l = 55\,in$ and $k = 2.5$, then the side length of the miniatures is:

$l' = \sqrt{\frac{l^{2}}{k} }$

$l' = \frac{l}{\sqrt{k}}$

$l' = \frac{55\,in}{\sqrt{2.5}}$

$l' \approx 34.785\,in$

The side length of the prints is approximately 34.785 inches.