Question

What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form?

Answer 1

Step-by-step explanation:

The function is as follows :

$f(x) = x^2 + 5x + 5$

We need to find the zeroes of the function in the simplest radical form.The zero of the above function is given by :

$x=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}$

Here,

b = 5

a = 1

c = 5

So,

$x=\dfrac{-5\pm \sqrt{5^2-4\times 1\times 5} }{2(1)}\\\\x=\dfrac{-5\pm \sqrt{25-20} }{2(1)}\\\\x=\dfrac{-5\pm \sqrt{5} }{2}$

Hence, the correct option is (c).