What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form?
1 answer:
Step-by-step explanation:
The function is as follows :
We need to find the zeroes of the function in the simplest radical form.The zero of the above function is given by :
Here,
b = 5
a = 1
c = 5
So,
Hence, the correct option is (c).
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-12(3 - 5)
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Easy remember (x^m)(x^n)=x^(m+n) basically add exponens when the base is same (13^-11)(13^16)(13^-3)(13^4)(13^-5)= 13^(-11+16-3+4-5)= 13^(5-4)= 13^1=13
Can someone help me? My grade is worth 40% and i dont want to fail
Move the constant to the other side, so that you have variable on one side and constant on the other side