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astraxan [27]
3 years ago
9

Solve bc-c^3 when b=8, and c=2.solve da^2 when d=7, and a=4.​

Mathematics
1 answer:
Novosadov [1.4K]3 years ago
7 0
56 because that’s what I torn
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Rewrite the expression in a radical form z^1/6
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Step-by-step explanation:

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7 0
3 years ago
The product of two rational numbers is 9⁄7 and one of them is 15⁄14. Then the other rational number is​
Rasek [7]

Answer:

The other rational number in the operation given is:

  • <u>6/5</u>

Step-by-step explanation:

To obtain the number in the operation given, we're gonna represent the operation:

  • r * 15/14 = 9/7

Where:

  • r = the other rational number.

Now we are going to solve r to identify its value in numbers:

  • r * 15/14 = 9/7
  • r = \frac{\frac{9}{7} }{\frac{15}{14}} (We pass a number that is multiplying to the left of the equal, to divide to the right of the equal symbol)
  • r = \frac{6}{5}

As you can see, when we operate, <u>the result is 6/5</u>, and we can prove this multiplying as we had in the original equation, replacing r by 6/5:

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  • 6/5 * 15/14 = 9/7
  • 9/7 = 9/7

In this form, we know the result is correct.

8 0
4 years ago
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