The answer is b x= 3
6 foot tall man has a 9 foot shadow at the same time a tree standing next to him as a 30 foot shadow how tall is the tree?
2 answers:
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Answer:
He invested $8500 with rate 3 1/5%
He invested $3000 with rate 3%
Step-by-step explanation:
* <em>Lets revise the rule of the simple interest</em>
- Simple interest I = PRT, where P in the money invested, R is the
interest rate and T is the time of investment
- Phyllis invested $11,500
- A portion earning a simple interest rate of 3 1/5% (3.2%) per year
- The rest earning a rate of 3% per year
- After one year the total interest earned on these investments
was $362.00
- We need to find the amount of money invested in each rate
* Assume that he invested $x with rate 3 1/5% and $y with rate 3%
∵ He invested $11,500 in both rates
∴ x + y = 11,500 ⇒ (1)
∵ He invested $x with 3 1/5%
∵ P = $x
∵ R = 3.2/100 = 0.032
∵ T = 1
∴
∴
∵ He invested $y with 3%
∵ P = $y
∵ R = 3/100 = 0.03
∵ T = 1
∴
∴
∵ The total interest was $362.00
- The total interest = +
∴ 0.032x + 0.03y = 362.00 ⇒ (2)
<em>We have system of equations</em>
x + y = 11,500 ⇒ (1)
0.032x + 0.03y = 362.00 ⇒ (2)
Multiply equation (1) by -0.03 to eliminate y
-0.03x - 0.03y = 345 ⇒ (3)
Add equations (2) and (3)
0.002x = 17
Divide both sides by 0.002
x = 8500
Substitute the value of x in equation (1)
8500 + y = 11,500
Subtract 8500 from both sides
y = 3000
* He invested $8500 with rate 3 1/5%
* He invested $3000 with rate 3%
Answer:
The area of the logo is
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
The area of a semicircle is equal to
so
The area of the logo is equal to multiply by 3 the area of one semicircle
we have
-----> the radius is half the diameter
substitute
Answer:
And we can find this probability with the following difference:
We can use the following commands on the ti 84
2nd>VARS>DISTR
And then we look for normalcdf and we input this:
normalcdf(0.7,1.4,0,1)
The other possible code would be:
normalcdf(-1000,1,4,0,1)-normalcdf(-1000,0.7,0,1)
And we got:
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
For this case we want to find this probability:
And we can find this probability with the following difference:
We can use the following commands on the ti 84
2nd>VARS>DISTR
And then we look for normalcdf and we input this:
normalcdf(0.7,1.4,0,1)
The other possible code would be:
normalcdf(-1000,1,4,0,1)-normalcdf(-1000,0.7,0,1)
And we got: