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Amanda [17]
3 years ago
11

6 foot tall man has a 9 foot shadow at the same time a tree standing next to him as a 30 foot shadow how tall is the tree?

Mathematics
2 answers:
ASHA 777 [7]3 years ago
8 0

Answer:

if u answer mines ill answer yours. and the other person hat answered is trying to hack you with that link they are sending it to everyone DO NOT CLICK THE LINK

Step-by-step explanation:

inna [77]3 years ago
5 0
27 feet? Or 20?
I did 9-7= 3 so 30-3=27
If not 9/7=1.5 so 30/1.5=20

?
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Write 30 in equality to describe this graph show your work will mark brainiest
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25 time 10 to the power of 5
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Step-by-step explanation:

6 0
4 years ago
A population of 280 flying squirrels in a town in Honduras is growing at a rate of 9% every 6 months. How many squirrels will th
VMariaS [17]

The 470 squirrels will be in 3 years, if a population of 280 flying squirrels in a town in Honduras is growing at a rate of 9% every 6 months.

Step-by-step explanation:

The given is,

                  280 flying squirrels

                  Growing at a rate of 9% every 6 months

Step:1

                 Formula to calculate the squirrels,

                                      y = A (1+r)^{t}...........................(1)

                 where, A = Initial count

                               r = Growing rate

                               t = Time

                  From the given,

                      A = 280 squirrels

                       r = 9 % = 0.09

                       t = 6        ( Growing rate is given for 6 months, for 3 years 36 months available, so t =\frac{36}{6} = 6)

                 From equation (1),

                               y =280(1+0.09)^{6}

                                  = 280 (1.09)^{6}

                                  = (280)(1.6771)

                                  = 469.588

             Squirrels after 3 years, y ≅ 470 squirrels

                                 ( or )

Step:1

            Year will be converted to months,

                       3 years = 36 months

           For 6 months,

                                     =( Squirrels count )( Rate of grow ) +Squirrels count

                                      = (280 × 0.09)+280 = 305.2 squirrels

           For 12 months,

                                     =( Squirrels count )( Rate of grow ) +Squirrels count

                                      = (305.2 × 0.09)+305.2 = 332.668 squirrels

             For 18 months,

                                     =( Squirrels count )( Rate of grow ) +Squirrels count

                                      = (332.668 × 0.09)+332.668 = 362.608 squirrels

           For 24 months,

                                     =( Squirrels count )( Rate of grow ) +Squirrels count

                                      = (362.608 × 0.09)+362.608 = 395.243 squirrels

            For 30 months,

                                     =( Squirrels count )( Rate of grow ) +Squirrels count

                                      = (395.243 × 0.09)+395.243 = 430.815 squirrels

             For 36 months,

                                     =( Squirrels count )( Rate of grow ) +Squirrels count

                                      = (430.815 × 0.09)+430.815 = 469.588 squirrels

               Squirrels after 3 years, y ≅ 470 squirrels

Result:

           The 470 squirrels will be in 3 years, if a population of 280 flying squirrels in a town in Honduras is growing at a rate of 9% every 6 months.

3 0
3 years ago
I really need help!!!
xenn [34]
(0,-2) (3,2)

m = -2-2 / 0-3 → m = -4/-3 → m = 4/3

y = 4/3x - 2

To check if your answer is correct, choose any of the two coordinates. Plug the x and y in the equation. For example, use (3,2).

2 = 4/3 (3) -2 → 2= 12/3 -2 → 2 = 4 - 2 → 2 = 2. So if you get an answer like this, it means it's correct.
8 0
3 years ago
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