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bearhunter [10]
2 years ago
5

My teacher didn’t give us the formula for this special right triangle so i don’t know how to even do it

Mathematics
1 answer:
vlabodo [156]2 years ago
8 0

Answer:

ask your teacher for help i think u need it and i can only provide that i don't understand it eitheir

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3×-y=5,2×+y=5 pleaseplease ​
Tanya [424]

Answer:

x = 2

y = 1

Step-by-step explanation:

3x - y = 5..............(1)× 1

2x + y = 5...….......(2)× 1

3x - y = 5..............(3)

2x + y = 5.............(4)

Cancel y

3x + 2x = 5 + 5

5x = 10

Divide both sides by 5

x = 2

Substitute for the value of y

3x - y = 5

3(2) - y = 5

6 - y = 5

6 - 5 = y

1 = y

y = 1

6 0
2 years ago
A rectangular swimming pool is twice as long as it is wide. A small concrete walkway surrounds the pool. The walkway is a 2 feet
Ksivusya [100]

Answer:

The width and the length of the pool are 12 ft and 24 ft respectively.

Step-by-step explanation:

The length (L) of the rectangular swimming pool is twice its wide (W):

L_{1} = 2W_{1}

Also, the area of the walkway of 2 feet wide is 448:

W_{2} = 2 ft

A_{T} = W_{2}*L_{2} = 448 ft^{2}

Where 1 is for the swimming pool (lower rectangle) and 2 is for the walkway more the pool (bigger rectangle).

The total area is related to the pool area and the walkway area as follows:

A_{T} = A_{1} + A_{w}    (1)          

The area of the pool is given by:

A_{1} = L_{1}*W_{1}        

A_{1} = (2W_{1})*W_{1} = 2W_{1}^{2}  (2)          

And the area of the walkway is:

A_{w} = 2(L_{2}*2 + W_{1}*2) = 4L_{2} + 4W_{1}    (3)          

Where the length of the bigger rectangle is related to the lower rectangle as follows:                  

L_{2} = 4 + L_{1} = 4 + 2W_{1}   (4)        

By entering equations (4), (3), and (2) into equation (1) we have:

A_{T} = A_{1} + A_{w}

A_{T} = 2W_{1}^{2} + 4L_{2} + 4W_{1}                

448 = 2W_{1}^{2} + 4(4 + 2W_{1}) + 4W_{1}            

224 = W_{1}^{2} + 8 + 4W_{1} + 2W_{1}

224 = W_{1}^{2} + 8 + 6W_{1}

By solving the above quadratic equation we have:

W₁ = 12 ft

Hence, the width of the pool is 12 feet, and the length is:

L_{1} = 2W_{1} = 2*12 ft = 24 ft

Therefore, the width and the length of the pool are 12 ft and 24 ft respectively.

I hope it helps you!                                                                                          

8 0
2 years ago
A submarine starts at sea level and travels to a position that is a little lower than −24 feet. Use the drop-down menus to compl
Black_prince [1.1K]

Answer:

  1. The submarine's position means the distance it traveled is greater than 24 feet
  2. A possible position of the submarine is -27 feet

Step-by-step explanation:

Distance is generally a positive number. (Displacement, or position may be negative, as in this case.) If the sub started at 0 feet and went lower than -24 feet, it traveled a distance of more than 24 feet (greater than 24 ft).

Of the numbers listed, the only one lower than -24 is -27.

7 0
3 years ago
-4n+3&gt;23<br> A. -5<br> B. 5<br> C. -9<br> D. -20<br> E. 20
Pani-rosa [81]
It will be 20 after u subtract
6 0
3 years ago
Write Three and eight thousandths in standard form? What is it
Lapatulllka [165]

Thousandths is the 3rd decimal place

The answer is 3.008

6 0
3 years ago
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