Here,a(n) = a + (n-1)d
Here, a = 5, d = 12-5 = 8, a(n) = 181
Substitute this values in to the expression,
181 = 5 + (n-1)8
181-5 = 8n-8
176+8 = 8n
n = 184/8
n = 23
So, it is 23th term of that Arithmetic Progression.
Hope this helps!
Given :
When 7 is subtracted from five times a number, the result is greater than twice the sum of the number and 4.
To Find :
All the numbers that satisfy the inequality.
Solution :
Let , the number is x .
Mathematical expression for first term is :
5x - 7
Mathematical expression for second term is :
2(x + 4)
Now , comparing both the expression by given constrain.

So, all the numbers that satisfy the inequality are greater than 5.
Hence , this is the required solution.
Answer:
= -15x +20
Step-by-step explanation:
-5(3x- 4)
= -5×3x- 4×-5
= -15x +20
Answer: x=3
y=4
Step-by-step explanation:
since both equations equal y then you can just make them equal
so 3x-5=-2x+10
3x=-2x+15
5x=15
x=3
y=3(3)-5
y=9-5
y=4
Answer:

Step-by-step explanation:
Given


Required

Initial expression of f(x) is 
From the question; we understand that f(x) was shifted down by 3 units;
This implies that

Also from the question; we understand that this new f(x) is equivalent to g(x);
In other words;

Substitute
and 
This gives

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Subtract 0.5x to both sides

Rearrange


Multiply both sides by -1


