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Setler79 [48]
3 years ago
12

What is the length of side c?

Mathematics
2 answers:
Sauron [17]3 years ago
7 0
Answer: 12cm

Hope this helps!! I used pythagorean theorem! my steps are in the picture, invade you have a similar problem later on!!

natulia [17]3 years ago
6 0
It’s 12cm and I can explain
You might be interested in
I need help in this section.
Phoenix [80]

Answer:

\frac{1}{45}

Step-by-step explanation:

There are

2 yellow

3 magenta

5 blue

marbles in the bag.

So total of 2 + 3 + 5 = 10 marbles

We have to multiply the probability of yellow on first pick by the probability of yellow on second pick (WITHOUT REPLACEMENT).

We denote P(Y1) as probability of yellow on first draw &

P(Y2) as probability of yellow on second draw

Thus,

P(Y1) = 2/10 = 1/5  [since 2 yellow and 10 total marbles]

Now,

P(Y2) = 1/9  [since now 1 yellow is taken out and NOT replaced, so we have 1 yellow remaining and total 9 marbles]

Now, we multiply:

P(Y1) * P(Y2) = 1/5 * 1/9 = 1/45

The probability is  \frac{1}{45}

6 0
3 years ago
Tavon has a gift card for $165 that loses $4 for each 30-day period it is not used. He has another gift card for $145 that loses
sweet [91]

Answer:

Equation 1 = Equation 2

165 - 4x = 145 - 3.50x

Step-by-step explanation:

Let x represent the number of 30-day periods.

Tavon has a gift card for $165 that loses $4 for each 30-day period it is not used.

Therefore the equation =

$165 -$4 × x

= 165 - 4x.......... Equation 1

He has another gift card for $145 that loses $3.50 for each 30-day period it is not used.

$145 -$3.50 × x

= 145 - 3.50x........... Equation 2

Hence, an equation for the number of 30-day periods until the value of the gift cards will be equal is obtained by equating Equation 1 and Equation 2 together

So, we have

Equation 1 = Equation 2

165 - 4x = 145 - 3.50x

We simplify further:

165 - 145 = -3.50 + 4.0x

20 = 0.5x

x = 20/0.5

x = 40

Therefore, number of each 30-day periods until the value of the gift cards will be equal is 40

3 0
3 years ago
What is the common factor for the following monomials 12x to the third power 18x to the second power 6 x to the fourth power
hichkok12 [17]

12x^3=\boxed{2}\cdot2\cdot\boxed{3}\cdot \boxed{x}\cdot \boxed{x}\cdot x\\\\18x^2=\boxed{2}\cdot\boxed{3}\cdot3\cdot \boxed{x}\cdot \boxed{x}\\\\6x^4=\boxed{2}\cdot\boxed{3}\cdot \boxed{x}\cdot \boxed{x}\cdot x\cdot x\\\\LCF(12x^3,\ 18x^2,\ 6x^4)=\boxed{2}\cdot\boxed{3}\cdot\boxed{x}\cdot\boxed{x}=6x^2\\\\Answer:\ \boxed{\boxed{6x^2}}

6 0
3 years ago
An opaque bag contains 5 green marbles 3 blue marbles and 2 red marbles. what is the of randomly picking out a marble and the ma
Elan Coil [88]

Answer:

1/5

Step-by-step explanation:

Since there are 2 red marbles and since there are a total of 10 marbles, the probability is 2/10. This simplifies to 1/5. So the probability of picking a red marble is 1/5.

4 0
4 years ago
If x = 6, y = 8, and z = 3.
wariber [46]
Where is the rest of the problem ?
6 0
3 years ago
Read 2 more answers
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