Answer:
56 ways.
Step-by-step explanation:
This question is solved by using combinations and permutations chapters in the math book.
To put it simply, we need to find the number of 3 horse combinations we can make from 8 horses. This requires the combinations formula:

here n is the total number of objects to choose from, and r is the number of objects we require in the combination or group.
Since there are 8 horses, n= 8
Since we need to choose only 3 of them, and order does not matter, r= 3
Solving the equation above using these inputs gives us 56 unique ways we can choose the three winners.
Range = 60-0=60
Median = 30
Interquartile Range = 35
(4^2 + 7) * 4 - 5 + 7
<em><u>Parentheses first.</u></em>
23 * 4 - 5 + 7
<em><u>Multiplication.</u></em>
92 - 5 + 7
<em><u>Subtraction.</u></em>
87 + 7
<em><u>Addition.</u></em>
94 is the final answer.
Answer:
A = -10
Step-by-step explanation:
Combine multiplied terms into a single fraction find common denominator etc etc.