PLS HELP WITH THIS FOR BRAINLIEST!!!!!!!

Mathematics

1 answer:

Yuliya22 [10]3 years ago

6 0

Answer:

30,063 Brainest pls I really need it

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If M is the set of all square of integers that are less than 100 and N is the set of all positive odd numbers that are under 15,

ollegr [7]

A set is simply the group of numbers.

The set of M and N are: $M = \{1,4,9,16,25,36,49,64,81\}$ and $N= \{1,3,5,7,9,11,13\}$ .
The set of M n N is: $M\ n\ N = \{1,9\}$ .
The set of M u N is: $M\ u\ N = \{1,3,4,5,7,9,11,13,16,25,36,49,64,81\}$

(a) The set of M and N

Given that:

M = squares of integers less than 100

N = Positive odd numbers less than 15

So, we have:

$M = \{1,4,9,16,25,36,49,64,81\}$

$N= \{1,3,5,7,9,11,13\}$

(b) M n N and M u N

M n N is the set of common elements between sets M and N.

So, we have:

$M\ n\ N = \{1,9\}$

M u N is the set of all elements in sets M and N.

So, we have:

$M\ u\ N = \{1,3,4,5,7,9,11,13,16,25,36,49,64,81\}$

Read more about sets at:

brainly.com/question/2332158

8 0

3 years ago

200/40+15 = ?? helpp mee ^^

wel

Answer:20 ^v^ Please follow me

Step-by-step explanation:

200/40=5

5+15=20

5 0

3 years ago

Read 2 more answers

Joseph has 24 cousins he has 6 more females than males how many females does he have?

Brums [2.3K]

Given that Joseph has 24 cousins, and he has 6 more females than males, the number of females will be obtained as follows;
suppose he had x males, number of females will be x+6.
The total will be:
x+(x+6)=24
x+x+6=24
2x+6=24
2x=24-6
2x=18
x=18/2
x=9
thus the number of male cousins is 9, the number of female cousins will be 9+6=15
We therefore conclude that he has 9 male cousins and 15 female cousins

6 0

3 years ago

F(x)= x^2– 3x + 9 g(x) = 3x^3+ 2x^2– 4x – 9 Find (f - g)(x).

denis-greek [22]

Answer:

$\large \boxed{\sf \ \ -3x^3-x^2+x+18 \ \ }$