The mid-point of FJ is the number right in the middle of FJ. Find the mean of F & J. Add regardless of sign
4 + 6 = 10
10/2 = 5
Add 5 to -4
5 + -4 = 1
H is your midpoint
True. As long as AB and BC are on the same line, AB + BC = AC
hope this helps
Answer:
Step-by-step explanation:
51 / 13 = 3.9231 = 3
51 - (13 x 3) = 12
Step-by-step explanation:
pop goes the weasel is quadratic formula song
The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.
Corresponding normal vectors of the planes are
<5,-1,-6> and <1,1,1>
We calculate the cross product as a determinant of (i,j,k) and the normal products
i j k
5 -1 -6
1 1 1
=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
=5i-11j+6k
=<5,-11,6>
Check orthogonality with normal vectors using scalar products
(should equal zero if orthogonal)
<5,-11,6>.<5,-1,-6>=25+11-36=0
<5,-11,6>.<1,1,1>=5-11+6=0
Therefore <5,-11,6> is a vector parallel to the line of intersection of the two given planes.
Answer:
the answer is 6
Step-by-step explanation:
6×3=18
So 6×5=30, 6×2=12
30-12=18
18=18
