Let's represent the two numbers by x and y. Then xy=60. The smaller number here is x=y-7.
Then (y-7)y=60, or y^2 - 7y - 60 = 0. Use the quadratic formula to (1) determine whether y has real values and (2) to determine those values if they are real:
discriminant = b^2 - 4ac; here the discriminant is (-7)^2 - 4(1)(-60) = 191. Because the discriminant is positive, this equation has two real, unequal roots, which are
-(-7) + sqrt(191)
y = -------------------------
-2(1)
and
-(-7) - sqrt(191)
y = ------------------------- = 3.41 (approximately)
-2(1)
Unfortunately, this doesn't make sense, since the LCM of two numbers is generally an integer.
Try thinking this way: If the LCM is 60, then xy = 60. What would happen if x=5 and y=12? Is xy = 60? Yes. Is 5 seven less than 12? Yes.
Answer:
y = 3x + 3
Step-by-step explanation:
If the entire line, or rather, the graph, is translated upwards by 5 units; the slope stays the same, but the y-intercept rises by 5 as well. Thus, the equation of the new graph would be;
y = 3x (-2+5)
y = 3x + 3
Answer: 118
Explanation:
Since ∠A=∠ADB: ∠ADB=61°. The sum of the interior angles of any triangle is 180°, thus:
61°+61°= 122
180-122=58°
∠DBA=58°
Since triangle BCD is an equilateral triangle, all the interior angles are the same:
180/3=60
∠DBC=60°
∠BCD=60°
∠CDB=60°
Since angles DBC and DBA make up angle ABC, just simply add the two angles together:
58+60=118°
Therefore, ∠ABC is 118°.
