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Feliz [49]
3 years ago
13

2HR 37MIN - 1HR 15 MIN

Mathematics
1 answer:
dlinn [17]3 years ago
6 0

Answer:

No

Step-by-step explanation:

2hours and 37min is not the equivilent to 1hour and 15min

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Consider a set of 7500 scores on a national test whose score is known to be distributed normally with a mean of 510 and a standa
german
\mathbb P(X>600)=\mathbb P\left(\dfrac{X-510}{85}>\dfrac{600-510}{85}\right)=\mathbb P(Z>1.059)\approx0.145

So approximately 14.5% of the scores are higher than 600. This means in a sample of 7500, one could expect to see 0.145\times7500\approx10.86 scores above 600.
5 0
3 years ago
How to substitute 3x+3y=-3 and y=5x-1?
schepotkina [342]
Since y = 5x-1, we can fill it into 3x + 3y = -3. First, let's look at relating to a simpler equation. Let's say that x + y = 9 and y = 3 + 5. Now, we can fill it in to get that x + (3 + 5) = 9. Now, we know that 3+5 is 8, so x + 8 = 9. Now, x = 1. Likewise, we can do the same. For 3x + 3y = -3, all we need to do is to switch the y in 3x + 3y = -3 with 5x - 1. So it would become 3x + 3(5x - 1) = -3. Now we distribute to get 3x + 15x - 3 = -3. Now add three to both sides to get 3x + 15x = 0. Now simplify to get 18x = 0. Now we know that x = 0. Now fill x into y = 5x - 1. So y = 5(0) - 1. Now we know that y = -1.

To check fill in the answer to 3x + 3y = -3.
3(0) + 3(-1) = -3
 0 + (-3) = -3
0 - 3 = -3
-3 = -3
Now that our check is completed we now know that x is 0 and y is -1.
7 0
3 years ago
A researcher took a random sample of 100 students from a large university. She computed a 95% confidence interval to estimate th
katen-ka-za [31]

Answer:

Part (A): The correct option is true.

Part (B): The null and alternative hypothesis should be:

H_o: \mu =0 ; H_a:\mu \neq0

Step-by-step explanation:

Consider the provided information.

Part (A)

A random sample of 100 students from a large university.

Increasing the sample size decreases the confidence intervals, as it increases the standard error.

If the researcher increase the sample size to 150 which is greater than 100 that will decrease the confidence intervals or the researcher could produce a narrower confidence interval.

Hence, the correct option is true.

Part (B)

The researcher wants to identify that whether there is any significant difference between the measurement of the blood pressure.

Therefore, the null and alternative hypothesis should be:

H_o: \mu =0 ; H_a:\mu \neq0

7 0
3 years ago
Can you find a strategy for splitting any number so that you always get the largest product?
Alex

9514 1404 393

Answer:

  split the number into equal pieces

Step-by-step explanation:

Assuming "splitting any number" means identifying parts that have the number as their sum, the maximum product of the parts will be found where the parts all have equal values.

We have to assume that the number being split is positive and all of the parts are positive.

<h3>2 parts</h3>

If we divide number n into parts x and (n -x), their product is the quadratic function x(n -x). The graph of this function opens downward and has zeros at x=0 and x=n. The vertex (maximum product) is halfway between the zeros, at x = (0 + n)/2 = n/2.

<h3>3 parts</h3>

Similarly, we can look at how to divide a (positive) number into 3 parts that have the largest product. Let's assume that one part is x. Then the other two parts will have a maximum product when they are equal. Their values will be (n-x)/2, and their product will be ((n -x)/2)^2. Then the product of the three numbers is ...

  p = x(x^2 -2nx +n^2)/4 = (x^3 -2nx^2 +xn^2)/4

This will be maximized where its derivative is zero:

  p' = (1/4)(3x^2 -4nx +n^2) = 0

  (3x -n)(x -n) = 0 . . . . . . . . . . . . . factor

  x = n/3  or  n

We know that x=n will give a minimum product (0), so the maximum product is obtained when x = n/3.

<h3>more parts</h3>

A similar development can prove by induction that the parts must all be equal.

6 0
3 years ago
Need help! :(((((((((((((((((((((((((
Vlada [557]

Answer:

\frac{1}{8}

Step-by-step explanation:

it's so simple dude

4 0
2 years ago
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