Let t = the cost of the tie and p = the cost of the pants
t + p = 87.76
We know the cost of the tie (t) is equal to 5.64 less than the pants then we can write:
t = p-5.64
Substitute back into the original equation
(p-5.64)+p=87.76
2p= 93.4
p=46.7
Substitute p back into the original equation
t+46.7= 87.76
t=41.06
We can verify this is true by adding them back together to get 87.76.
Answer:
Step-by-step explanation:
We want to determine a 95% confidence interval for the mean salary of all graduates from the English department.
Number of sample, n = 400
Mean, u = $25,000
Standard deviation, s = $2,500
For a confidence level of 95%, the corresponding z value is 1.96. This is determined from the normal distribution table.
We will apply the formula
Confidence interval
= mean ± z × standard deviation/√n
It becomes
25000 ± 1.96 × 2500/√400
= 25000 ± 1.96 × 125
= 25000 ± 245
The lower end of the confidence interval is 25000 - 245 =24755
The upper end of the confidence interval is 25000 + 245 = 25245
Therefore, with 95% confidence interval, the mean salary of all graduates from the English department is between $24755 and $25245
Answer:
girl. . I wanna say 80 but don't count on my answer. hopefully I helped
To solve a proportion, you can either use cross products or basic multiplication.
To do cross products, you would multiply 17 (1st numerator) by 6 (2nd denominator).
Do the same with the other diagonal angle, 3 times y.
You'll end up with 3y = 102.
To solve for y, you divide both sides by 3.
102 ÷ 3 = 34
y = 34
The other way you could solve this is to see that 6 is 2 times as large as 3, so you would multiply 17 by 2 to get an equal proportion.
3 × 2 = 6
17 × 2 = 34
Your final answer is y = 34. Hope this helps! :)