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2 years ago

Can someone explain this / answer, Its a picture

Mathematics

1 answer:

UkoKoshka [18]2 years ago

8 0

Answer:

option c is the correct answer (l=1 cm and w=42cm)

Step-by-step explanation:

length(l) = 1.00cm

width(w)= 42.00 cm

ACCORDING TO FORMULA

Area of rectangle = l×w

=1 cm × 42 cm

= 42cm^2

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What is the volume of the pyramid?

geniusboy [140]

Answer: 16 cm^2.

Step-by-step explanation: The volume of a pyramid is equal to one-third the product of the area of the base and the height:

$V=\frac{1}{3}A*h$

In this case, the base is a square, so its area is:

A=L^2 where "L" is the lenght of the base edge

So the volume would be:

$V=\frac{1}{3}L^{2} *h$

$V=\frac{1}{3}4^{2} *3$

V=16*3/3

$V=16cm^{2}$

7 0

2 years ago

Please answer correctly !!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!!

Nonamiya [84]

Answer:

Step-by-step explanation:

Pythagorean Theorem:

25^2=24^2+x

625=576+x^2

49=x^2

x=sqrt49

x=7

Hope this helps!

Merry Christmas!

8 0

2 years ago

Read 2 more answers

Complete parts (a) through (c) below.

Yuki888 [10]

Answer:

a) $t_{crit}= 1.34$

b) $t_{crit}=-2.539$

c) $t_{crit}=\pm 2.228$

Step-by-step explanation:

Part a

The significance level given is $\alpha=0.1$ and the degrees of freedom are given by:

$df = n-1= 15$

Since we are conducting a right tailed test we need to find a critical value on the t distirbution who accumulates 0.1 of the area in the right and we got:

$t_{crit}= 1.34$

Part b

The significance level given is $\alpha=0.01$ and the degrees of freedom are given by:

$df = n-1= 20-1=19$

Since we are conducting a left tailed test we need to find a critical value on the t distirbution who accumulates 0.01 of the area in the left and we got:

$t_{crit}=-2.539$

Part c

The significance level given is $\alpha=0.05$ and $\alpha/2 =0.025$ and the degrees of freedom are given by:

$df = n-1= 11-1=10$

Since we are conducting a two tailed test we need to find a critical value on the t distirbution who accumulates 0.025 of the area on each tail and we got:

$t_{crit}=\pm 2.228$

4 0

2 years ago

Suppose you want to know how fast you traveled from the park to the library. As you moved, your speed varied from second to seco

frutty [35]

Step-by-step explanation:

In order to describe speed of an object, we must describe the average speed of the entire trip. It is equal to the distance moved divided by time taken.

If a person covers a distance of 1 km to the library in 15 minutes, we can find its average speed.

Firstly, we convert 15 minutes to hour, 15 min = 0.25 hours

Now, using formula of speed = distance/time

$v=\dfrac{1\ km}{0.25\ h}\\\\v=4\ km/h$

It means that the average speed of the person is 4 km/h. Hence, the given statement is true.

6 0

2 years ago

2n-7/3 = 15 solve for n

WITCHER [35]

$2n- \frac{7}{3} =15$
$2n- \frac{7}{3} =15$ common denominator is 3
$3(2n- \frac{7}{3} )=3*15$ distributhing 3 through parantheses
$3*2n- \frac{3*7}{3}=3*15$
$3*2n-7=3*15$
$6n-7=45$ add7
$6n=45+7$
$6n=52$ divide by 6
$n= \frac{52}{6}$ simplify
$n=8 \frac{2}{3}$ ⇒ $\frac{26}{3}$

5 0

2 years ago