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2 years ago

Using the slope formula, determine the slope of the two points.

1 answer:

5 0

The slope formula is is rise over run or y2-y1/x2-x1

If you plug in those numbers you will get

(-1)-(-4)
———
1-(-2)

Simplify it and you get

3
— or 1
3

So the slope is 1

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8000$ is invested in an account the yields 6% interest per year. After how many years will the account worth 13709.60$ if the in

ozzi

Answer:

After 9 years the account will be worth 13709.60$

Step-by-step explanation:

We are given the following in the question:

We are given the following in the question:

P = $8000

r = 6% = 0.046

n = 12

The compound interest is given by:

$A = p\bigg(1+\dfrac{r}{n}\bigg)^{nt}$

where A is the amount, p is the principal, r is the interest rate, t is the time in years.

Putting the values, we get,

$13709.60 = 8000\bigg(1+\dfrac{0.06}{12}\bigg)^{12t}\\\\\dfrac{13709.60}{8000} = \bigg(1+\dfrac{0.06}{12}\bigg)^{12t}\\\\\Rightarrow 1.7137 = (1.005)^{12t}\\\Rightarrow t \approx 9$

Thus, after 9 years the account will be worth 13709.60$

5 0

3 years ago

Read 2 more answers

Please help, thank you :)

wolverine [178]

Answer:

y^6

Step-by-step explanation:

$\frac{y}{1} \times \frac{{y}^{5} }{1}$

${y}^{6}$

7 0

2 years ago

A sociologist was investigating the ages of grandparents of high school students. From a random sample of 10 high school student

umka2103 [35]

Answer:

$(69.8-71.6) -2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= -8.908$

$(69.8-71.6) +2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= 5.308$

So then the confidence interval for the difference of means is given by:

$-8.908 \leq \mu_M -\mu_F \leq 5.308$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X_{M}= 69.8$ represent the mean for the age of grandmother

$\bar X_{F}= 71.6$ represent the mean for the age of grandfather

$s_{M}= 8.38$ represent the sample deviation for the age of grandmother

$s_{F}= 6.65$ represent the sample deviation for the age of grandfather

$n_M = n_F= 10$

Solution to the problem

For this case the confidence interval is given by:

$(\bar X_{M} -\bar X_F) \pm t_{\alpha/2} \sqrt{\frac{s^2_M}{n_M} +\frac{s^2_F}{n_F}}$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n_M +n_F-2=10+10-2=18$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,18)".And we see that $t_{\alpha/2}=2.101$