<span>Jared can run 520 yards in one minute and you are asked to change the unit to feet/second. One yard will be equal to 3 feet. One minute equal to 60 seconds. Then, the speed would be:
(520 yards/minute )* (3 feet/yard) / (60 second/minute)= 26 feet/second</span>
Answer:
162-x=180
x=342
Step-by-step explanation:
Answer:
A) 34.13%
B) 15.87%
C) 95.44%
D) 97.72%
E) 49.87%
F) 0.13%
Step-by-step explanation:
To find the percent of scores that are between 90 and 100, we need to standardize 90 and 100 using the following equation:

Where m is the mean and s is the standard deviation. Then, 90 and 100 are equal to:

So, the percent of scores that are between 90 and 100 can be calculated using the normal standard table as:
P( 90 < x < 100) = P(-1 < z < 0) = P(z < 0) - P(z < -1)
= 0.5 - 0.1587 = 0.3413
It means that the PERCENT of scores that are between 90 and 100 is 34.13%
At the same way, we can calculated the percentages of B, C, D, E and F as:
B) Over 110

C) Between 80 and 120

D) less than 80

E) Between 70 and 100

F) More than 130

I'm pretty sure the answer is 24
The answer is the 2 one Bc it was the divided