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vredina [299]
2 years ago
11

Help plsssssss i need explanation or not just give anser pls

Mathematics
1 answer:
alekssr [168]2 years ago
4 0

Answer:

true

Step-by-step explanation:

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a school librarian ordered new books for the library. 1/3 are science 2/5 are biography and the rest of the books are fiction. W
Fantom [35]

i think it would be 4/15 because science is 6/15 and fiction is 5/15

i don't need it but brainliest is appreciated

4 0
3 years ago
Read 2 more answers
What is the difference? StartFraction 2 x + 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x + 5 Over x cubed minu
Sunny_sXe [5.5K]

Answer:

<h2>\frac{(x + 5)(x + 2)}{ {x}^{3} - 9x }</h2>

First option is the correct option.

Step-by-step explanation:

\frac{2x + 5}{ {x}^{2} - 3x }  -  \frac{3x + 5}{ {x}^{3} - 9x }  -  \frac{x + 1}{ {x}^{2} - 9 }

Factor out X from the expression

\frac{2x + 5}{x(x - 3)}  -  \frac{3x + 5}{x( {x}^{2}  - 9)}  -  \frac{x + 1}{ {x}^{2}  - 9}

Using {a}^{2}  -  {b}^{2}  = (a - b)(a + b) , factor the expression

\frac{2x + 5}{x(x - 3)}  -  \frac{3x + 5}{x(x - 3)(x + 3) }  -  \frac{x + 1}{(x - 3)(x + 3)}

Write all numerators above the Least Common Denominators x ( x - 3 ) ( x + 3 )

\frac{(x + 3) \times (2x - 5) - (3x + 5) - x \times (x + 1)}{x(x - 3)(x + 3)}

Multiply the parentheses

\frac{2 {x}^{2}  + 5x + 6x + 15 - (3x + 5) - x(x + 1)}{x(x - 3)(x + 3)}

When there is a (-) in front of an expression in parentheses, change the sign of each term in the expression

\frac{2 {x}^{2}  + 5x + 6x + 15 - 3x - 5 - x \times (x + 1)}{x(x - 3)(x + 3)}

Distribute -x through the parentheses

\frac{2 {x}^{2}  + 5x + 6x + 15 - 3x - 5 -  {x}^{2} - x }{x(x - 3)(x + 3)}

Using {a}^{2}  -  {b}^{2}  = (a + b)(a - b) , simplify the product

\frac{2 {x}^{2}  + 5x + 6x + 15 - 3x - 5 -  {x}^{2}  - x}{x( {x}^{2}  - 9)}

Collect like terms

\frac{ {x}^{2}  + 7x + 15 - 5}{x( {x}^{2}  - 9)}

Subtract the numbers

\frac{ {x}^{2}  + 7x + 10}{ x({x}^{2}   - 9)}

Distribute x through the parentheses

\frac{ {x}^{2}  + 7x + 10}{ {x}^{3}  - 9x}

Write 7x as a sum

\frac{ {x}^{2} + 5x +2x + 10 }{ {x}^{3} - 9x }

Factor out X from the expression

\frac{x(x + 5) + 2x + 10}{ {x}^{3}  - 9x}

Factor out 2 from the expression

\frac{x( x + 5) + 2(x + 5)}{ {x}^{3} - 9x }

Factor out x + 5 from the expression

\frac{(x + 5)(x + 2)}{ {x}^{3} - 9x }

Hope this helps...

Best regards!!

6 0
3 years ago
Read 2 more answers
Please help with this question.
Aneli [31]

Answer:

if I have my calculations right it would be £120

6 0
3 years ago
Nine times the difference of a number and one is equal to seven less than two times the number
Oksana_A [137]
9*(x-1)=2x-7
First get rid of your parenthesis by distributing. 
9x-9=2x-7
Then all you have to do is isolate the variable
9x=2x+2
7x=2
so x= 2/7


8 0
2 years ago
Simplify (5^1/3)^3.
pentagon [3]

Answer:

The correct option is C. 5

Therefore,

(5^{\frac{1}{3})^{3}\ =\ \d5

Step-by-step explanation:

Simplify

(5^{\dfrac{1}{3})^{3}=?

Solution:

Using Identity

(x^{a})^{b}=x^{(a\times b)}

So in the given expression

x = 5\\a=\dfrac{1}{3}\\\\b=3

Therefore,

(5^{\frac{1}{3})^{3}\ =\ \d5^{(\dfrac{1}{3}\times 3)}=\d5^{1}=\d5

Therefore,

(5^{\frac{1}{3})^{3}\ =\ \d5

6 0
3 years ago
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