Answer:
-2 + 11h
Step-by-step explanation:
To simplify this equation, you can first combine like terms:
( -1 + -1 ) + ( -3h + -8h )
-2 + -11h
Answer:
HIG=28°
Step-by-step explanation:
HI is a diameter therefore it's measure is 180°
HI-IG=HG
180-128=HG
52°=HG
HIG=1/2HG
HIG=1/2(56°)
HIG=28°
The paraboloid meets the x-y plane when x²+y²=9. A circle of radius 3, centre origin.
<span>Use cylindrical coordinates (r,θ,z) so paraboloid becomes z = 9−r² and f = 5r²z. </span>
<span>If F is the mean of f over the region R then F ∫ (R)dV = ∫ (R)fdV </span>
<span>∫ (R)dV = ∫∫∫ [θ=0,2π, r=0,3, z=0,9−r²] rdrdθdz </span>
<span>= ∫∫ [θ=0,2π, r=0,3] r(9−r²)drdθ = ∫ [θ=0,2π] { (9/2)3² − (1/4)3⁴} dθ = 81π/2 </span>
<span>∫ (R)fdV = ∫∫∫ [θ=0,2π, r=0,3, z=0,9−r²] 5r²z.rdrdθdz </span>
<span>= 5∫∫ [θ=0,2π, r=0,3] ½r³{ (9−r²)² − 0 } drdθ </span>
<span>= (5/2)∫∫ [θ=0,2π, r=0,3] { 81r³ − 18r⁵ + r⁷} drdθ </span>
<span>= (5/2)∫ [θ=0,2π] { (81/4)3⁴− (3)3⁶+ (1/8)3⁸} dθ = 10935π/8 </span>
<span>∴ F = 10935π/8 ÷ 81π/2 = 135/4</span>
Answer:
(A) 0.125 probability
(B) 0.625 probability
(C) 660 miles
Step-by-step explanation:
The distance driven by a truck driver daily, falls between 300miles and 700miles and follows a uniform distribution.
(A) The probability that the truck driver goes more than 650 miles a day is:
[700 - 650] / [700 - 300] = 50/400 = 0.125
(B) The probability that the truck driver goes between 400 and 650 miles a day is:
[650 - 400] / [700 - 300] = 250/400 = 0.625
(C) The minimum number of miles the truck driver travels on the furthest 10% of days is given thus:
10% of 400 = 40
Subtract this from the farthest distance;
700miles - 40miles = 660miles
