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3 years ago

Please help i need the answer asap!!!

Mathematics

2 answers:

IrinaVladis [17]3 years ago

7 0

Choice b because it it now where’s my brainliest

MA_775_DIABLO [31]3 years ago

5 0

Answer:

Choice b.

Step-by-step explanation:

Replace (x, y) with (1, 1) and verify if the equations are correct.

You would ignore the x and y in the equations. Testing one of each pair.

a. 3 + 2 = 3, incorrect
b. 7 + 2 = 9, correct
c. 8 + 1 = 7, incorrect
d. 8 - 2 = 4, incorrect

It is obvious that only b. is correct.

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5x-(x+1)=5-2x i dont understand what to do. Plz help

Vlada [557]

Answer:

x=1

Step-by-step explanation:

5x-(x+1)=5-2x

distribute

5x-x-1 = 5-2x

4x-1 = 5-2x

add 2x on each side

4x-1+2x = 5-2x+2x

6x -1 = 5

add 1 on each side

6x-1+2 = 5+1

6x = 6

divide by 6

6x/6 = 6/6

x = 1

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3 years ago

What is the solution -7=-3x+5+2x<br>

poizon [28]

Answer:

12 = x

Step-by-step explanation:

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3 years ago

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Find the indicated confidence interval. Assume the standard error comes from a bootstrap distribution that is approximately norm

Olegator [25]

Answer:

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3 years ago

The distance on a map between two locations is 2.25 inches. If = 24 miles, what the actual distance between the two locations?

almond37 [142]

The answer would be C.

2.25 + 24 = 26.25 miles

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3 years ago

Which of these choices show a pair of equivalent expressions? Check all that apply.

AleksAgata [21]

The main rule we use in this exercise is

$( \sqrt{a} ) ^{m} =( a^{ \frac{1}{2}} )^{m} = a^{ \frac{1}{2}*m}=a^{ \frac{m}{2}}$

and the more general case:

$( \sqrt[n]{a} ) ^{m} =( a^{ \frac{1}{n}} )^{m} = a^{ \frac{1}{n}*m}=a^{ \frac{m}{n}}$
Using these rules, we make all the indices, or exponents, look like $a^{ \frac{m}{n}}$ , and compare them to each other.

A. $( \sqrt{8} )^{9} = ( 8^{ \frac{1}{2}} )^{9} = 8^{ \frac{1}{2}*9}= 8^{ \frac{9}{2}}$

B. $( \sqrt{4} ) ^{5} =( 4^{ \frac{1}{2}} )^{5} = 4^{ \frac{1}{2}*5}=4^{ \frac{5}{2}}$

C. $( \sqrt[3]{125} ) ^{7} =( 125^{ \frac{1}{3}} )^{7} = 125^{ \frac{1}{3}*7}= 125^{ \frac{7}{3}}$

D. $( \sqrt{12} ) ^{7} =( 12^{ \frac{1}{2}} )^{7} = 12^{ \frac{1}{2}*7}=12^{ \frac{7}{2}}$

4 0

3 years ago

Read 2 more answers