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3 years ago

Please help i need the answer asap!!!

Mathematics

2 answers:

IrinaVladis [17]3 years ago

7 0

Choice b because it it now where’s my brainliest

MA_775_DIABLO [31]3 years ago

5 0

Answer:

Choice b.

Step-by-step explanation:

Replace (x, y) with (1, 1) and verify if the equations are correct.

You would ignore the x and y in the equations. Testing one of each pair.

a. 3 + 2 = 3, incorrect
b. 7 + 2 = 9, correct
c. 8 + 1 = 7, incorrect
d. 8 - 2 = 4, incorrect

It is obvious that only b. is correct.

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Simplify 3/2 (x+3/4) - (x+1)

fiasKO [112]

Answer:

If I had to guess, it would be the first option. Any calculator program I put it into is giving me 4x+1/8

Step-by-step explanation:

Sorry I wasn't able to help much, good luck though!

6 0

3 years ago

Read 2 more answers

Write the equation of the line parallel to the given line and passing through the given point. y= 1/2 x+2 through (0,4)

marshall27 [118]

Parallel lines have the same slope, so the slope of the new line is 1/2.

The line passes through (0,4), and this gives the y-intercept, which would equal 4.

The equation now would be: y = 1/2x + 4

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3 years ago

Find the Area of the Garden (Must show work!!!)

sesenic [268]

Answer:

162 ft²

Step-by-step explanation:

The missing side of the garden is the hypotenuse of a triangle with legs:

(80 - 70) = 10 ft and (40 - 15) = 25 ft

The length of the side is:

$\sqrt{10^2+ 25^2} = \sqrt{725}$ ≈ 27 ft

The area of the garden is:

A = 27*6 = 162 ft²

7 0

3 years ago

Evaluate the equation for the indicated value, f(n)=5n+8 for f(4),

Colt1911 [192]

You would need to put 4 in for (n)so, 5(4)+8 then solve. 5 times 4=20 plus 8 is 28. I hope I could help!

7 0

3 years ago

Find the area between y = 8 sin ( x ) y=8sin⁡(x) and y = 8 cos ( x ) y=8cos⁡(x) over the interval [ 0 , π ] . [0,π]. (Use decima

Marina86 [1]

Answer:

0.416 au

Step-by-step explanation:

Let y1=8sin(x) and y2=8cos(x), we must find the area between y1 and y2

$\int\limits^\pi _0{(8cos(x)-8sin(x))} \, dx = 8\int\limits^\pi _0{(cos(x)-sin(x))} \, dx =\\8(sin(x)+cos(x)) evaluated(0-\pi )=\\8(sin(\pi )-sin(0))+8(cos(\pi )-cos(0))=\\8(0.054-0)+8(0.998-1)=8(0.054)+8(-0.002)=0.432-0.016=0.416$

3 0

3 years ago