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2 years ago

ZA and ZB are vertical angles. If m_A = (7x– 20)° and m_B = (6x – 1)º,

Mathematics

1 answer:

Arlecino [84]2 years ago

7 0

$\\ \sf\longmapsto 7x-20=6x-1$

$\\ \sf\longmapsto 7x-6x=-1+20$

$\\ \sf\longmapsto x=-19$

Now

$\\ \sf\longmapsto m$

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Use synthetic division to solve (2x^3+4x^2-35x+15) divided by (x-3) What is the quotient?

Salsk061 [2.6K]

Answer:

Step-by-step explanation:

The only thing you need to watch carefully is the divisor which in this case is x - 3. The divisor, in synthetic division, is the number that will make the binomial go to 0.

x - 3 =0

x = 3

So the divisor is 3.

3 || 2 4 -35 15

6 30 -15

======================

2 10 -5 0

So the quotient is

2x^2 + 10x - 5 with no remainder

7 0

3 years ago

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Factorize 225-49<br><img src="https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20" id="TexFormula1" title=" {x}^{2} " alt=" {x}^{2}

erica [24]

$225-49x^2$

$-49x^2+225$

$=(7x+15)(-7x+15)$

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3 years ago

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What is the slope of the line passing through (-3, 5) and (5, -3)?

saveliy_v [14]

we know that

the formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

in this problem we have

$A(-3,5)\ B(5,-3)$

substitute the values in the formula

$m=\frac{-3-5}{5+3}$

$m=\frac{-8}{8}$

$m=-1$

therefore

<u>the answer is the option</u>

$slope=-1$

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3 years ago

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birth weights in norway are normally distributed with a mean of 3570 g and a standard deviation of 500g. if the hospital officia

Svetradugi [14.3K]

Answer:

2630 g

Step-by-step explanation:

From the given information:

Given that:

mean (μ) = 3750 g

Standard deviation (σ) = 500

Suppose the hospital officials demand special treatment with a percentage of lightest 3% (0.03) for newborn babies;

Then, the weight of birth that differentiates the babies that needed special treatment from those that do not can be computed as follows;

P(Z < z₁) = 0.03

Using the Excel Formula; =NORMSINV(0.03) = -1.88

z₁ = - 1.88

Using the test statistics z₁ formula:

$z_1 = \dfrac{X-\mu}{\sigma}$

$-1.88 = \dfrac{X-3570}{500}$

By cross multiply, we have:

-1.88 × 500 = X - 3570

-940 = X - 3570

-X = -3570 + 940

-X = -2630

X = 2630 g

Hence, 2630 g is the required weight of birth that differentiates the babies that needed special treatment from those that do not

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2 years ago

What is the solution to this system of equations?

ololo11 [35]

Answer:

(1,5) is the answer

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2 years ago