(0, 4) and (4,0)<br> Rate of Change: <br> b=

The HCF and LCM of two numbers x and 126 are 24 and 840 respectively. Find the value of x.

Zigmanuir [339]

Answer:

x=160

Step-by-step explanation:

x×126=24×840

$x=\frac{24 \times840}{126} =160$

8 0

3 years ago

88+88+88+88+88+88+88+88 times 88=_________

Nastasia [14]

Answer:

It's your friend at school. 8360 is your answer.

Step-by-step explanation:

88 + 88

= 176 + 88

= 264 + 88

= 352 + 88

= 440 + 88

= 528 + 88

= 616 + 88 =

704 x 88

= 8360

3 0

3 years ago

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What is the domain of the square root function graphed below?

Nikolay [14]

The domain of a function is the set of all values x can have.
From the graph, we see the least value of x is 3. x can be any value greater than or equal to 3.

The domain is

$x \ge 3$

5 0

4 years ago

Consider a uniform distribution from aequals4 to bequals29. (a) Find the probability that x lies between 7 and 27. (b) Find th

weeeeeb [17]

Answer:

a) 80% probability that x lies between 7 and 27.

b) 28% probability that x lies between 6 and 13.

c) 44% probability that x lies between 9 and 20.

d) 28% probability that x lies between 11 and 18.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value x between c and d, in which d is larger than c, is given by the following formula.

$P(c \leq x \leq d) = \frac{d - c}{b - a}$

Uniform distribution from a = 4 to b = 29

(a) Find the probability that x lies between 7 and 27.

So $c = 7, d = 27$

$P(7 \leq x \leq 27) = \frac{27 - 7}{29 - 4} = 0.8$

80% probability that x lies between 7 and 27.

(b) Find the probability that x lies between 6 and 13. 

So $c = 6, d = 13$

$P(6 \leq x \leq 13) = \frac{13 - 6}{29 - 4} = 0.28$

28% probability that x lies between 6 and 13.

(c) Find the probability that x lies between 9 and 20.

So $c = 9, d = 20$

$P(9 \leq x \leq 20) = \frac{20 - 9}{29 - 4} = 0.44$

44% probability that x lies between 9 and 20.

(d) Find the probability that x lies between 11 and 18.

So $c = 11, d = 18$

$P(11 \leq x \leq 18) = \frac{18 - 11}{29 - 4} = 0.28$

28% probability that x lies between 11 and 18.

3 0

3 years ago

20x^2-30=4x solve for x

ankoles [38]

Answer:

x=1.3288 or -1.1288

Step-by-step explanation:

Given $20x^{2}-30=4x$

Subtract 4x from both sides

$20x^{2}-4x-30=0$

Since we can factor out 2 from whole equation, let's factor out 2.

$2(10x^{2}-2x-15)=0$

Divide with 2 on both sides

$10x^{2}-2x-15=0$

We got the quadratic equation, we can solve for x using quadratic formula.

$x=\frac{-b\pm\sqrt{b^{2}-4ac} } {2a}$

$x=\frac{2\pm\sqrt{2^{2}-4X10X(-15)} } {2X10}$

$x=\frac{2\pm\sqrt{604} }{20}$

$x=\frac{2\pm2\sqrt{151}}{20}$

$x=1.3288or-1.1288$

8 0

3 years ago

Read 2 more answers

(0, 4) and (4,0) Rate of Change: b=