Graph the inverse variation

Allen wants to have a mean of 90 on his math quizzes. So far, he has scored 86, 94, 88, 95, and 89. What is the least score that

viva [34]

Answer:

88

Step-by-step explanation:

$\frac{86 + 94 + 88 + 95 + 89 + x}{6} = 90$

The mean would be the sum of all the math quiz grades divided by the number of quizzes taken.

Solve for x:

$86 + 94 + 88 + 95 + 89 + x = 540$

$452 + x = 540$

$x = 88$

Thus, Allen needs at least an 88 to obtain a mean of at least 90.

3 0

3 years ago

A company that teaches self-improvement seminars is holding one of its seminars in Middletown. The company pays a flat fee of $1

Nutka1998 [239]

Answers:

To reach the breakeven point, how many attendees will that take? <u> 117 </u>

What will be the company's total expenses and revenues? <u> $1755 for each </u>

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Explanation:

x = number of attendees

C(x) = cost function for the company

C(x) = 14x+117

This is because the company pays $14 per person, so x of them accounts for 14x dollars. Then we add on the flat fee of $117 to get 14x+117 dollars overall.

In contrast, the revenue is

R(x) = 15x

because each attendee brings in $15 for the company

The breakeven point is when the cost and revenue are the same. This produces a profit of $0.

R(x) = C(x)

15x = 14x+117

15x-14x = 117

x = 117

If 117 people attend the seminar, then the company breaks even.

To check this, we'll compute the cost and revenue

C(x) = 14x+117

C(117) = 14*117+117

C(117) = 1755

R(x) = 15x

R(117) = 15*117

R(117) = 1755

The cost and revenue is $1755 for each. Because we get the same value, this confirms the correct x value.

Since 117 people is the breakeven point, the company should aim for an attendee count above this, so they can get a positive profit. At some point, there is a max capacity so x can't go up forever.

7 0

2 years ago

A manager wants to know if the mean productivity of two workers is the same. For a random selection of 30 hours in the past mo

vekshin1

Answer:

A.The data should be treated as paired samples. Each pair consists of an hour in which the productivity of the two workers is compared.

Explanation:

If the mean productivity of two workers is the same.

For a random selection of 30 hours in the past month, the manager compares the number of items produced by each worker in that hour.

There are two samples and the productivity of the two men is paired for each hour.

7 0

3 years ago

PLEASE HELPP !! The ceiling of Stacy's living room is a square that is 25 ft long on each side. Stacy knows the diagonal of the

EleoNora [17]

Answer:

a) d = 36 ft. ( using Pithagoras´theorem )

b) d = 36 ft ( Using ( function sin ) trigonometry

Step-by-step explanation:

a) Using Pythagoras´Theorem:

Diagonal (d) is the hypothenuse of a right triangle of side 25 feet, and according to Pythagoras´Theorem in a right triangle.

d² = a² + b²

In this particular case a = b = 25 feet then

d² = (25)² + ( 25)²

d = √ 2 * (25)²

d = √2 * 25

d = 1,414*25

d = 35,35

d = 36 ft.

b) Using trigonometry:

We know that sin 45° = cos 45° = √2 / 2

In a right triangle

sin α = opposite side / hypothenuse (d)

sin 45° = √2 / 2 = 25/ d

√2 *d = 2* 25

d = 50/√2

d = 50 / 1,414

d = 35,36

d = 36 ft

6 0

3 years ago

Find the 9th term of the geometric sequence whose common ratio is 1/3 and whose first term is 2.

raketka [301]

Answer:

2/6561

Step-by-step explanation:

Geometric sequence formula : $a_n=a_1(r)^n^-^1$

where an = nth term, a1 = first term , r = common ratio and n = term position

given ratio : 1/3 , first term : 2 , given this we want to find the 9th term

to do so we simply plug in what we are given into the formula

recall formula : $a_n=a_1(r)^n^-^1$

define variables : a1 = 2 , r = 1/3 , n = 9

plug in values

a9 = 2(1/3)^(9-1)

subtract exponents

a9 = 2(1/3)^8

evaluate exponent

a9 = 2 (1/6561)

multiply 2 and 1/6561

a9 = 2/6561

7 0

2 years ago