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3 years ago

14

ABC is similar to XYZ. The length of AB is 3 inches. The length of BC is 5 inches. The length of YZ is 13 inches. What is the le

ngth, in inches of XY

1 answer:

Marrrta [24]3 years ago

5 0

Answer:

7.8

Step-by-step explanation:

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How do u solve y=2/3x-4

poizon [28]

The answer is 2 y= 2 so 3•2=6 6-4=2

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3 years ago

Bananas are .95/1 pound, what is the constant of proportionality?

Sidana [21]

Since y is .95 and x is 1 it is a unit rate which is the constant of proportionality.

Correct me if I am wrong.

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3 years ago

Identify the measure of PR in the diagram. PLEASE HELP!!

kykrilka [37]

Answer:

The correct answer is : Fourth, PR = 6

Step-by-step explanation:

PR is mid segment ( median line) of the side YZ in the triangle XYZ and is equal it's half.

PR = 1/2 YZ = 1/2 · 12 = 6

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3 0

3 years ago

HELP PLEASE!!! Thanks!

Irina18 [472]

Answer:

2) $\frac{\sqrt{77}}{11}$

3) 5√2

Step-by-step explanation:

Simplest radical form of an expression is the expression in radical so that there are no more square roots, cube roots, 4th roots, etc left to find, after rationalising the denominator ( if needed ).

2. Here the given expressions,

$\frac{\sqrt{7}}{\sqrt{11}}$

For rationalising the denominator multiply both numerator and denominator by √11,

$\frac{\sqrt{77}}{11}$

3. given expression,

$\sqrt{50}$

$=\sqrt{25\times 2}$

$=\sqrt{25}\times \sqrt{2}$ $(\because \sqrt{ab}=\sqrt{a}\sqrt{b})$

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8 0

3 years ago

A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks along the x-axis from the spotlight toward the bui

Sedbober [7]

Answer:

0.675 m/s

Step-by-step explanation:

Let height of shadow= y,CD=x

Height of man=2 m

Speed of man= $\frac{dx}{dt}=1. 8 m/s$

$\triangle ABD\sim\triangle ECD$

Therefore, $\frac{AB}{EC}=\frac{BD}{CD}$

$\frac{y}{2}=\frac{12}{x}$

$xy=24$

Differentiate w.r.t t

$x\frac{dy}{dt}+y\frac{dx}{dt}=0$

$x\frac{dy}{dt}=-y\frac{dx}{dt}$

$\frac{dy}{dt}=-\frac{y}{x}\frac{dx}{dt}$

When the man is 4 m from the building

Then, we have x=12-4=8 m

$\frac{dx}{dt}=1.8 m/s$

Substitute the values in above equation then, we get

$8y=24$

$y=\frac{24}{8}=3$

Substitute the values then we get

$\frac{dy}{dt}=-\frac{3}{8}\times 1.8=-0.675 m/s$

Hence, the length of his shadow on the building decreasing at the rate 0.675 m/s.

8 0

3 years ago